[SOLVED] Converting object to class

[ars_moriendi]

Thanks everyone for all the help you've been.

Now, I'm having a problem in that, when I turn my code into a class, it fails to instantiate. I've looked at the documentation for how PHP treats objects--fairly simple--and I'm stumped. I know I'm missing something obvious.

Any ideas?

 

<?php

class eventList	
{
$stack = array();
$tagname="";
function create($filename)
{	
	if (! ($xmlparser = xml_parser_create()) )
	{ 
	   die ("Cannot create parser");
	}

	function start_tag($parser, $name, $attribs) 
	{
		global $tagname;
		$tagname = $name;
	}
	function end_tag($parser, $name) {
	}
	function tag_contents($parser, $data) {
		global $tagname;
		global $stack;
		$stack[$tagname]=$data;
	}
	xml_set_element_handler($xmlparser, "start_tag", "end_tag");
	xml_set_character_data_handler($xmlparser, "tag_contents");

	if (!($fp = fopen($filename, "r"))) 
	{ 
		die("cannot open ".$filename); 
	}

	while ($data = fread($fp, 4096))
	{
	 	$data=eregi_replace(">"."[[:space:]]+"."<","><",$data);
	   	if (!xml_parse($xmlparser, $data, feof($fp))) 
		{
		  	$reason = xml_error_string(xml_get_error_code($xmlparser));
		  	$reason .= xml_get_current_line_number($xmlparser);
		  	die($reason);
	   	}
	}
	xml_parser_free($xmlparser);
}
}
$event1=new eventList();
$event1->create("http://www.example.com/rss.xml");

?>

[per1os]

class eventList	
{
var $stack = array();
var $tagname="";
function create($filename)
{	
	if (! ($xmlparser = xml_parser_create()) )
	{ 
	   die ("Cannot create parser");
	}

	function start_tag($parser, $name, $attribs) 
	{
		global $tagname;
		$tagname = $name;
	}
	function end_tag($parser, $name) {
	}
	function tag_contents($parser, $data) {
		global $tagname;
		global $stack;
		$stack[$tagname]=$data;
	}
	xml_set_element_handler($xmlparser, "start_tag", "end_tag");
	xml_set_character_data_handler($xmlparser, "tag_contents");

	if (!($fp = fopen($filename, "r"))) 
	{ 
		die("cannot open ".$filename); 
	}

	while ($data = fread($fp, 4096))
	{
	 	$data=eregi_replace(">"."[[:space:]]+"."<","><",$data);
	   	if (!xml_parse($xmlparser, $data, feof($fp))) 
		{
		  	$reason = xml_error_string(xml_get_error_code($xmlparser));
		  	$reason .= xml_get_current_line_number($xmlparser);
		  	die($reason);
	   	}
	}
	xml_parser_free($xmlparser);
}
}
$event1=new eventList();
$event1->create("http://www.example.com/rss.xml");

?>

 

Parse error for one, turn on display_errors and error_reporting to E_ALL and report any more errors.

[ars_moriendi]

Sorry, I wanted to change my post, but I missed the time limit. The PHP install on my laptop has consistently failed time and again. Not sure why. Never had the time to figure it out. So, I have to upload my code to a shared hosting server to test.

Is the error tracking something I can still do on shared hosting?

 

[per1os]

Sorry, I wanted to change my post, but I missed the time limit. The PHP install on my laptop has consistently failed time and again. Not sure why. Never had the time to figure it out. So, I have to upload my code to a shared hosting server to test.

Is the error tracking something I can still do on shared hosting?

 

 

Should be

 

www.php.net/display_errors

www.php.net/error_reporting

 

It is good to be disabled in production enviroments, but for testing you want them to show all errors.

[ars_moriendi]

Sorry, I wanted to change my post, but I missed the time limit. The PHP install on my laptop has consistently failed time and again. Not sure why. Never had the time to figure it out. So, I have to upload my code to a shared hosting server to test.

Is the error tracking something I can still do on shared hosting?

 

 

Should be

 

www.php.net/display_errors

www.php.net/error_reporting

 

It is good to be disabled in production enviroments, but for testing you want them to show all errors.

 

Okay, I added

error_reporting(E_ALL);

error_reporting(E_PARSE);

to the top of my script. No screen output. I checked my logs with the hosting company: nothing yet. On the other hand, the logs they (Globat) supply me look like they came out of a chron job so I may not get any error information until tomorrow.

 

 

[per1os]

www.php.net/ini_set

 

ini_set("display_errors", "on");
error_reporting(E_ALL);

 

Try putting those at the top and see if it reports the error.

[ars_moriendi]

Okay,

I put the following code at the top of my script, including the parse error line separately because evidently E_ALL doesn't pick those up:

ini_set("display_errors", "on");

error_reporting(E_ALL);

error_reporting(E_PARSE);

$p = getcwd();

error_log("ERRORS!", 3, $p."/my-errors.log");

I was hoping to redirect the error log to my working directory, but I'm still coming up with bupkiss.

 

 

[ars_moriendi]

Okay,

I put the following code at the top of my script, including the parse error line separately because evidently E_ALL doesn't pick those up:

ini_set("display_errors", "on");

error_reporting(E_ALL);

error_reporting(E_PARSE);

$p = getcwd();

error_log("ERRORS!", 3, $p."/my-errors.log");

Before you say it--yes, I know that error log on line 5 was pointless.

I tried both ini_set('display_errors','1'); and ini_set("display_errors", "on");

Any idea why these won't display to the page?

 

 

[ars_moriendi]

Solution:

Class variables not preceeded by var keyword:

Example:

class someclass
{
   $tagname="";  // WRONG
   var $tagname="";  // RIGHT
}

[Barand]

Have a look at the first reply to your topic by frost110 and note the "var" kewords