kristin Lai Posted March 30, 2006 Share Posted March 30, 2006 Okay, I can't for the life of me figure out what's wrong with this query but I keep getting the "not a valid result resource" error message. I've checked that the db fieldname is spelled correctly and there is a value stored in the $image variable so any suggestions would really help. Here's the query:[code=php:0]$queryImg = "SELECT * FROM images WHERE imgID=$image";$resultImg = mysql_query($queryImg) or die ("could not retrieve image");$rowImg = mysql_fetch_array($queryImg,MYSQL_ASSOC);extract ($rowImg);[/code] Quote Link to comment https://forums.phpfreaks.com/topic/6181-query-wont-work/ Share on other sites More sharing options...
shocker-z Posted March 30, 2006 Share Posted March 30, 2006 You need[code=php:0]$queryImg = "SELECT * FROM images WHERE imgID='$image'";$resultImg = mysql_query($queryImg)or die ("could not retrieve image");$rowImg = mysql_fetch_array($queryImg,MYSQL_ASSOC);extract ($rowImg);[/code]as '$image' show's it as a string but without the '' it looks for it as a field :) Quote Link to comment https://forums.phpfreaks.com/topic/6181-query-wont-work/#findComment-22326 Share on other sites More sharing options...
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