Making this script work

[almightyegg]

I have a script that I went through in a tutorial except it left a few bits out...

 

function createRequestObject() { 

   var req; 

   if(window.XMLHttpRequest){ 
      // Firefox, Safari, Opera... 
      req = new XMLHttpRequest(); 
   } else if(window.ActiveXObject) { 
      // Internet Explorer 5+ 
      req = new ActiveXObject("Microsoft.XMLHTTP"); 
   } else { 
      // There is an error creating the object, 
      // just as an old browser is being used. 
      alert('Problem creating the XMLHttpRequest object'); 
   } 

   return req; 

}

   // Make the XMLHttpRequest object 
   var http = createRequestObject();

function sendRequest(act) { 

   // Open PHP script for requests 
   http.abort; 
   http.open('post', 'delete.php'); 
   http.setRequestHeader('Content-Type', 'application/x-www-form- 
      urlencoded'); 
   http.send('act='+act); 

}

   if(http.readyState == 4 && http.status == 200){ 

      // Text returned FROM the PHP script 
      var response = http.responseText; 

      if(response) { 
         // UPDATE ajaxTest content 
         document.getElementById("ajaxTest").innerHTML = response; 
      } 

   } 

} 

<input type="button" value="Send AJAX Request" id="sendButton"
   onClick="sendRequest('test1');" />

 

Basically, I'm a newbie to AJAX and JS so there are probably lots of errors here...

the script I want to execute (delete.php) is this:

<?
include 'db.php'; // Connect to DB
$email = $_COOKIE['email']; 
$password = $_COOKIE['password']; 

$sql = mysql_query("SELECT * FROM users WHERE email='$email' AND password='$password' AND activated='1'"); 
$mem = mysql_fetch_array($sql);

$id = $_GET['t'];
$f = $_GET['f'];
$deletepost = mysql_query("DELETE FROM topics WHERE id = '$id' and fid = '$f' LIMIT 1");
$delpos = mysql_query($deletepost);

?>

 

As you can see this requires two PHP variables...$t and $f, that go into a URL like so: delete.php?t=$t&f=$f what I need help with is getting this information into the AJAX script (I think it's the sendRequest() part)

 

anyway thanks in advance