image upload question

[showoff]

hi, i just wanted to say first that some of the stuff on this site has helped me thus far.

ok my question is i followed a tut about making a image upload script to add to my site. i got that working, my only main question is what do i need to do to get it to give me the url of the image. when it is uploaded, somewhat like photobucket or other image hosting sites do. what i am doing is i do graphic design work mostly signatures and wallpapers, and i put together a site to show my stuff, but i have a forum( a free one for now) and some of my users we want to make a flash gallery but for now i want it to were they can host stuff to share between us for now. i hope my question makes sense, i know enough about html but am very new to php, i also have a mysql database on my server. if using that is better or easier i noticed some of the ones i have seen do that but i really don't want all the stuff that the one i found has on it. thanks in advance.

[btherl]

Please post your current code

[showoff]

this what i have and it will upload but i just want to add were it will show the link back to the image.

 

<form enctype="multipart/form-data" action="upload.php" method="POST">
Please choose a file: <input name="uploaded" type="file" /><br />
<input type="submit" value="Upload" />
</form> 
<?php 
$target = "upload/"; 
$target = $target . basename( $_FILES['uploaded']['name']) ; 
$ok=1; 

//This is our size condition 
if ($uploaded_size > 1000000) 
{ 
echo "Your file is too large.<br>"; 
$ok=0; 
} 

//This is our limit file type condition 
if ($uploaded_type =="text/php") 
{ 
echo "No PHP files<br>"; 
$ok=0; 
} 

//Here we check that $ok was not set to 0 by an error 
if ($ok==0) 
{ 
Echo "Sorry your file was not uploaded"; 
} 

//If everything is ok we try to upload it 
else 
{ 
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) 
{ 
echo "The file ". 
basename( $_FILES['uploadedfile']['name']). " has been uploaded"; 
} 
else 
{ 
echo "Sorry, there was a problem uploading your file."; 
} 
} 

?>