[SOLVED] Need help with this small code

[davidspan]

I have tried this many different ways still can't get it to work

 

<?php
if ((the_author_ID()) == 4){
        echo'boo';
}else{
echo'not boo';
}
?>

 

It's not getting a value so it just prints 4not boo... What am I doing wrong

[soycharliente]

What is the_author_ID()?

[davidspan]

it's a wordpress tag, it does print 4

[soycharliente]

Maybe it returns a string. Try quoting 4.

[davidspan]

no tried '4' & "4"

 

the only documentation I could find was here

 

http://codex.wordpress.org/Template_Tags/the_author_ID

[soycharliente]

Try abstracting it out and saving it to a variable.

[davidspan]

went right over my head...

 

I was able to find out it's a function

 

function get_the_author_ID() {
  58      global $authordata;
  59      return $authordata->ID;
}

[soycharliente]

Well Yeah it's a function.

 

Try this:

<?php
$var = the_author_ID();
echo ($var == 4) ? "boo" : "not boo";
?>

[davidspan]

no I tried that earlier in a little different format, tried it again still not working

[soycharliente]

I </3 wordpress. I had to setup a blog for my company and they wanted to use the K2 theme and mod almost everything. It took forever. Learned a lot though. However, not what could help you ATM.

 

Have you tried posting in the wp specific forums? They would probably be more equipped to help you.

http://wordpress.org/support/

[davidspan]

I haven't tried it only because they take forever....

 

And never really answer you

[davidspan]

ok I replaced the_author_ID() and now it's working $authordata->ID

[Grodo]

Try this

<?php
if ((the_author_ID())= '4')
       echo 'boo';
else
echo 'not boo';
?>

 

or

 

Try this

<?php
if (the_author_ID()= '4')
       echo 'boo';
else
echo 'not boo';
?>

 

or

 

 

Try this

 

<?php
$author = the_author_ID();
if ($author = '4')
       echo 'boo';
else
echo 'not boo';
?>