xtiancjs Posted March 31, 2006 Share Posted March 31, 2006 Hi all, I have a form which updates values in a dB table, is it possible from the same form to also insert a value into a different table? I just want to log the form users ip address with $_server['REMOTE_ADDR']; and use that ip later to limit form submission Here is my form code: form method="post" name="form2" action="<?php echo $editFormAction; ?>"> <table align="center"> <tr valign="baseline"> <td nowrap align="right"><select name="broker_rating_two" onClick="DoSubmission2();"> <?php do { ?> <option value="<?php echo $row_valueset2['value']?>" <?php if (!(strcmp($row_valueset2['value'], $row_bprofile['broker_rating_two']))) {echo "SELECTED";} ?>><?php echo $row_valueset2['value']?></option> <?php} while ($row_valueset2 = mysql_fetch_assoc($valueset2));?> </select></td> <td></td> <tr> </table> <input type="hidden" name="id" value="<?php echo $row_bprofile['id']; ?>"> <input type="hidden" name="broker_num_votes_two" value="<?php echo $row_bprofile['broker_num_votes_two']; ?>"> <input type="hidden" name="MM_update" value="form2"> <input type="hidden" name="id" value="<?php echo $row_bprofile['id']; ?>"> </form>HERE IS MY FORM ACTION CODE:$editFormAction = $_SERVER['PHP_SELF'];if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']);}if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE brokers SET broker_rating= broker_rating + %s, broker_num_votes=%s + 1 WHERE id=%s", GetSQLValueString($_POST['broker_rating'], "int"), GetSQLValueString($_POST['broker_num_votes'], "int"), GetSQLValueString($_POST['id'], "int")); mysql_select_db($database_broker, $broker); $Result1 = mysql_query($updateSQL, $broker) or die(mysql_error());}APOLS FOR ALL THE CODEXtian Quote Link to comment Share on other sites More sharing options...
wildteen88 Posted March 31, 2006 Share Posted March 31, 2006 Yes you can you just have to make another query to the database after your other query. I believe this is your query:[code] $updateSQL = sprintf("UPDATE brokers SET broker_rating= broker_rating + %s, broker_num_votes=%s + 1 WHERE id=%s",GetSQLValueString($_POST['broker_rating'], "int"),GetSQLValueString($_POST['broker_num_votes'], "int"),GetSQLValueString($_POST['id'], "int"));mysql_select_db($database_broker, $broker);$Result1 = mysql_query($updateSQL, $broker) or die(mysql_error());[/code]After [i]GetSQLValueString($_POST['id'], "int"));[/i] do your secound query to log the users IP address. Quote Link to comment Share on other sites More sharing options...
xtiancjs Posted April 1, 2006 Author Share Posted April 1, 2006 [!--quoteo(post=360445:date=Mar 31 2006, 02:03 PM:name=wildteen88)--][div class=\'quotetop\']QUOTE(wildteen88 @ Mar 31 2006, 02:03 PM) [snapback]360445[/snapback][/div][div class=\'quotemain\'][!--quotec--]Yes you can you just have to make another query to the database after your other query. I believe this is your query:[code] $updateSQL = sprintf("UPDATE brokers SET broker_rating= broker_rating + %s, broker_num_votes=%s + 1 WHERE id=%s",GetSQLValueString($_POST['broker_rating'], "int"),GetSQLValueString($_POST['broker_num_votes'], "int"),GetSQLValueString($_POST['id'], "int"));mysql_select_db($database_broker, $broker);$Result1 = mysql_query($updateSQL, $broker) or die(mysql_error());[/code]After [i]GetSQLValueString($_POST['id'], "int"));[/i] do your secound query to log the users IP address.[/quote]Thanks for the reply, that is a big help as I wasn't sure where to start my next query from, will give it a shot thanks againxtian Quote Link to comment Share on other sites More sharing options...
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