[SOLVED] if(substr etc ||| How to tell if username is under limit and display error?

[Technex]

Hey guys I javascript:void(0);

Coolhope you can guess what I'm trying to do just by seeing this:

 

if(substr($_POST['regusername'],0,25)==TRUE){

echo 'Username is good under 25';

}else{

echo 'Username is bad more than 25';

}

 

 

 

Just doesn't work I think what I'm trying to == to is wrong.

 

Thanks! 

[cooldude832]

No i can' tell what you are doing, are you trying to get the length of user name so they can't have names >25 characters?

[Technex]

Sorry lemme explain it more.

 

 

I already know how to limit the username by using this: $regusername = substr($_POST['regusername'],0,25);

 

But if a user goes over this limit it just cuts there username down to 25 and doesn't tell them or stop them from registering. How can I display a error and stop the code?

 

 

(by using a if statement if possible)

[lewis987]

if(strlen($regusername) <= 25){
//Code
}
else
{
//code
}

 

strlen() check the length of a string...

that WILL work if you use the correct var..

[Technex]

Thanks mate, solved. Nice surprise coming up on MSN with that code also .