Jump to content

[SOLVED] Help with function


Adam1239

Recommended Posts

Hi, i have a function that checks a users hand to see if its a Short straight or not. The code is:

 

function Is_ShortStraight($test)
{
  for ( $i = 1; $i < 7; $i++ ) {
  $for[$i] = substr_count($test, $i); } 
  if($for[1] == "1" && $for[2] == "1" && 
     $for[3] == "1" && $for[4] == "1" OR 
     $for[2] == "1" && $for[3] == "1" && 
     $for[4] == "1" && $for[5] == "1" OR 
     $for[3] == "1" && $for[4] == "1" && 
     $for[5] == "1" && $for[6] == "1"){ 
  return true; 
  }else{ 
  return false; 
}
}

 

This was working ok untill i had a short straight like this 3-4-5-6-3 and this function returned false, because the bit of the function

$for[3] == "1" && $for[4] == "1"  is basically saying if there is one 3 and one 4 in the hand when it is not one 3 because that last number could be anything. Do you know a way round this?

 

Thanks.

Link to comment
Share on other sites

A few questions for you...

 

1.  What format does the variable $test come in?  Is it a series of numbers separated by spaces?  Just a long string?

 

2.  What purpose does comparing the individual items of the array to the number "1" do?

 

Get back to me when you  have time and I'll take a further look into this.

Link to comment
Share on other sites

A few questions for you...

 

1.  What format does the variable $test come in?  Is it a series of numbers separated by spaces?  Just a long string?

 

2.  What purpose does comparing the individual items of the array to the number "1" do?

 

Get back to me when you  have time and I'll take a further look into this.

 

Hi, thanks for your intrest, the test comes in 5 numbers separated by - like this:

 

$test = "6-2-3-4-5"

if( Is_ShortStraight($test) )
  {
    echo "$test is a short straight";
}else{
   echo "$test is not a short staight";
}

 

Also for the second question the  $for[$i] = substr_count($test, $i); }  part counts how meny times the number $i as come up in the $test string. so you could put it like this: if the said number comes up once.

Link to comment
Share on other sites

Prereq = $seqCount == number of elements in array

 

<?php

# Find a method of discovering if any part of the string is sequential between high, low.
# Ex: 1 4 3 2 5 - returns true
# Ex: 1 4 6 4 3 - returns false, no 5

$string = "1 4 3 2 2";
$string2 = "1 4 3 2 5";

print checkString($string, 5); #false
print checkString($string2, 5); #true

function checkString($string, $seqCount) {
        $string = explode(" ", $string);
#       print_r($string);
        for($number = 0; $number <= $seqCount; $number++) {
                if( in_array($string[$number] + 1, $string) && (in_array($string[$number] - 1, $string) || $string != 0)) {
                        foreach($string as $num) {
                                $flag = 1;
                                if($num == $string[$number])
                                        $flag++;
                        }
                        if ($flag < 2)
                                $count++;

                }
        }
        print "matched $count <br>";
        if($count >= $seqCount) return true;
        return false;
}

#print sort($string);

 

Seems to work for me :)

Link to comment
Share on other sites

Prereq = $seqCount == number of elements in array

 

<?php

# Find a method of discovering if any part of the string is sequential between high, low.
# Ex: 1 4 3 2 5 - returns true
# Ex: 1 4 6 4 3 - returns false, no 5

$string = "1 4 3 2 2";
$string2 = "1 4 3 2 5";

print checkString($string, 5); #false
print checkString($string2, 5); #true

function checkString($string, $seqCount) {
        $string = explode(" ", $string);
#       print_r($string);
        for($number = 0; $number <= $seqCount; $number++) {
                if( in_array($string[$number] + 1, $string) && (in_array($string[$number] - 1, $string) || $string != 0)) {
                        foreach($string as $num) {
                                $flag = 1;
                                if($num == $string[$number])
                                        $flag++;
                        }
                        if ($flag < 2)
                                $count++;

                }
        }
        print "matched $count <br>";
        if($count >= $seqCount) return true;
        return false;
}

#print sort($string);

 

Seems to work for me :)

 

If you try your code with the string as $string = "4 2 3 6 5"; to match 5 seen as this is for a dice game, and there are 6 dice sides, it will only match 3. But very good example to what i came up with  :P

Link to comment
Share on other sites

try

<?php
$straight = array (1,2,3,4,5,6);

$hand = "3-4-5-2-3";
$ha = explode('-', $hand);
sort ($ha);
for ($i=0; $i<3; $i++) {
    $tmp = array_slice($straight,$i,4);
    if ($tmp == array_intersect($tmp, $ha))
        echo 'Found: ', join('-', $tmp);
}
?>

 

Hi thanks for your help, the code works, just i need this to be in a function which returns true if it as a match or false if it as not got a match. so if i use the if($tmp == array_intersect($tmp, $ha)) return true; else return false; would it work?

Link to comment
Share on other sites

<?php
function shortStraight($hand)
{
    $straight = array (1,2,3,4,5,6);

    $ha = explode('-', $hand);
    sort ($ha);
    for ($i=0; $i<3; $i++) {
        $tmp = array_slice($straight,$i,4);
        if ($tmp == array_intersect($tmp, $ha))
            return true;
    }
    return false;
}

$hand = "2-4-6-2-3";

echo shortStraight($hand) ? 'Yes'  : 'No' ;
?>

Link to comment
Share on other sites

<?php
function shortStraight($hand)
{
    $straight = array (1,2,3,4,5,6);

    $ha = explode('-', $hand);
    sort ($ha);
    for ($i=0; $i<3; $i++) {
        $tmp = array_slice($straight,$i,4);
        if ($tmp == array_intersect($tmp, $ha))
            return true;
    }
    return false;
}

$hand = "2-4-6-2-3";

echo shortStraight($hand) ? 'Yes'  : 'No' ;
?>

 

Thank you much appreciated.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.