mattzo Posted August 15, 2007 Share Posted August 15, 2007 Hi I just started working with php and mysql. I have tried searching the net and the forums for a solution however all related posts I have trouble understanding. The result I would like is for the page to list all of the dvd titles from the 'dvds' table and bold the title if the the dvd_id matches any of the udvd_id in the 'userdvds' table. Here is an example: dvds dvd_id dvd_title 1 title 1 2 title 2 3 title 3 userdvds userdvd_id udvd_id 1 3 2 1 The tables above will produce: title 1 title 2 title 3 <?php require_once ('./includes/config.inc.php'); ?> <?php require_once ('../mysql_connect_local.php'); // Connect to the local db. // Count the number of records $query = "SELECT COUNT(*) FROM dvds ORDER BY dvd_title ASC"; $result = @mysql_query ($query); $row = mysql_fetch_array ($result, MYSQL_NUM); $num_records = $row[0]; // Make the query. $query = "SELECT dvd_id, dvd_title, udvd_id, userdvd FROM dvds, userdvds ORDER BY dvd_title ASC"; $result = @mysql_query ($query); // Run the query. while ($row = mysql_fetch_array($result, MYSQL_ASSOC)){ if ($row['udvd_id'] == $row['dvd_id']) { $bold = '<strong>' . $row['dvd_title'] . '</strong>'; } else { $bold = '' . $row['dvd_title'] . ''; } echo '<table><tr bgcolor=""> <td align="center">' . $row['dvd_id'] . '</td> <td align="left">' . $bold . '</td> </tr></table>'; } mysql_free_result ($result); // Free up the resources. mysql_close(); // Close the database connection. ?> This however duplicates the result from the first table depending on how many rows I have in the second table and for some reason the one of the results of each row doesnt become bolded eg: 1 title 1 1 title 1 2 title 2 2 title 2 Thank you for your patience, I have been stuck on this problem for days. Quote Link to comment https://forums.phpfreaks.com/topic/65005-solved-check-one-table-for-same-value-with-another/ Share on other sites More sharing options...
GingerRobot Posted August 15, 2007 Share Posted August 15, 2007 I would do this with a subquery to select the number of rows where dvd_id = udvd_id. Then bold the records depending on if this is 1 or 0: <?php include('test_db_connection.php'); $sql = "SELECT `dvd_title`,`dvd_id`, (SELECT COUNT(*) FROM `userdvds` WHERE`udvd_id`=`dvd_id`) as `count` FROM `dvds` ORDER BY `dvd_title` ASC"; $result = mysql_query($sql) or die(mysql_error()); echo '<table><tr><td>DVD ID</td><td>DVD TITLE</td></tr>'; while($row = mysql_fetch_assoc($result)){ if($row['count'] == 1){ $id = '<b>'.$row['dvd_id'].'</b>'; $title = '<b>'.$row['dvd_title'].'</b>'; }else{ $id = $row['dvd_id']; $title = $row['dvd_title']; } echo '<tr><td>'.$id.'</td><td>'.$title.'</td></tr>'; } ?> </table> Produces: <table><tr><td>DVD ID</td><td>DVD TITLE</td></tr> <tr><td><b>1</b></td><td><b>title 1</b></td></tr> <tr><td>2</td><td>title 2</td></tr> <tr><td><b>3</b></td><td><b>title 3</b></td></tr> </table> I think thats what you're after. Quote Link to comment https://forums.phpfreaks.com/topic/65005-solved-check-one-table-for-same-value-with-another/#findComment-324430 Share on other sites More sharing options...
mattzo Posted August 15, 2007 Author Share Posted August 15, 2007 thank you very much! That was exactly what I needed Quote Link to comment https://forums.phpfreaks.com/topic/65005-solved-check-one-table-for-same-value-with-another/#findComment-324453 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.