Jump to content

Recommended Posts

I have 2 functions and I use one function inside another but inside the first function I have a varible that I want to use in the second functions and it doesn't seem to work. Let me give you an example:

 

<?php
function a()
{
      $a = bob;
}

function b()
{
      a();
      echo $a;
}
?>

 

I know that is stupid but it's an example! The thing is that php won't echo $a. Why?

Link to comment
https://forums.phpfreaks.com/topic/65317-solved-functions/
Share on other sites

because $a isn't defined in the scope of the second function.  everything that occurs within a function is restricted to its scope, unless it is passed upward to the caller using return or was passed to the function via reference in the first place:

 

<?php
function a()
{
      $a = 'bob';
      return $a;
}

function b()
{
      $a = a();
      echo $a;
}
?>

Link to comment
https://forums.phpfreaks.com/topic/65317-solved-functions/#findComment-326202
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.