Jump to content

Grouped radio button with image which has javascript for onclick


shocker-z

Recommended Posts

I have a problem with my grouped radio button when i click the image it doesn't selct the radio button too.. it does highlight the radio button so i know it's partly correct but i think it may be the javascript for displaying the main image that is stopping it from being selected..

anyone?

see here [a href=\"http://blucode.sytes.net/ukchat/index.php\" target=\"_blank\"]http://blucode.sytes.net/ukchat/index.php[/a] login details
Username: shocker-z
Password: [blank]
by blank i mean totaly blank! :)

Here is all the code i'm using

[code]
<?
if ($_SESSION['logged_in']) {
?>
<script language="javascript">
function switch1(div) {
if (document.getElementById('1')) {
var option=['1','2','3'];
for(var i=0; i<option.length; i++)
{ obj=document.getElementById(option[i]);
obj.style.display=(option[i]==div)? "block" : "none"; }
}
}
//
function switchImg(i){
document.images["wine"].src = i;
}
</script>


<table width="450" border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td width="300" align="left" valign="top"><p class="fright"><img src="profiles/nopic.gif" id="wine" height="300" width="300" alt="" /></p></td>
    <td width="150" valign="top"><div class="fright"></div>
      <div align="center">
        <?php
$img_query=mysql_query("SELECT username,ID,description FROM images WHERE username='$session_username' LIMIT 3");
$i=0;
while ($img=mysql_fetch_array($img_query)) {
$i++;
if ($img) {
$id=$img['ID'];
$cat2=$cat.'/';
?>
      </div>
      <hr align="center" />
      <div align="center">
        <input type="radio" name="del_picture" id="<?php echo $id; ?>" accesskey="<?php echo $id; ?>" checked> <label for="<?php echo $id; ?>">pic <?php echo $id; ?>
        <img src="<?php echo($cat2.'thumbs.php?id='.$id); ?>" onclick="switchImg('<?php echo($cat2.'view.php?id='.$id); ?>')" checked="checked" /></label>
      </div>
      <hr align="center" />
      <div align="center">
  <?php
} else {
echo('no image');
}
$i++;
}
?>
  </div>
    </div></td>
  </tr>
</table>
<p>
  <label></label>
  <?php
} else {
        if (!$_SESSION['logged_in']) {
            echo("You are not logged in!");
        }
}?>
</p>[/code]


Regards
Liam
Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.