[SOLVED] Flaw with .printf

[director87]

Hi all.

 

I'm coding a simple commentary page which calls to an AJAX function I've created. The code below prints the path of the link outside as text, when I want the path as the URL for the link!

 

echo "<a href=\"javascript:llamarasincrono('".printf('%s?pageNum_Recordset1=%d%s', $currentPage, min($totalPages_Recordset1, $pageNum_Recordset1 + 1), $queryString_Recordset1)."', 'commentarios');\">Next</a>";

 

an example of the output would be:

 

 

/jose/commentarios.php?pageNum_Recordset1=1&totalRows_Recordset1=9&user_fk=31 Next

 

 

When it should just print the link:

 

Next 

 

I'm absolutely stuck. I hope I explained this somewhat efficiently... I'm sure it has to do with the etiquette of my quotations. Please let me know if my explanation is clear enough. All help is appreciated!!! 

 

Saludos,

Mark

[MadTechie]

try this

echo "<a href=\"javascript:llamarasincrono('".printf('%s?pageNum_Recordset1=%d%s', $currentPage, min($totalPages_Recordset1, $pageNum_Recordset1 + 1), $queryString_Recordset1)."', 'commentarios');."\">Next</a>";

[MadTechie]

option #2 (as a backup)

$x = min($totalPages_Recordset1, $pageNum_Recordset1 + 1);
echo "<a href=\"javascript:llamarasincrono('$currentPage?pageNum_Recordset1=$x$queryString_Recordset1', 'commentarios');\">Next</a>";

[director87]

The 2nd works perfect.

 

Thanks,

Mark