asphalt43 Posted August 21, 2007 Share Posted August 21, 2007 Hello, I have trouble with my snippet running livehost. It is a simple image gallery. I have thumbs that pass variables to the snippet through the address bar. // html link example: ?id=55&pid=in10 I had it running live but then it stopped refreshing the images after the page was loaded. It changes the images only when I navigate to another menu id. It works ok localhost. etomite 0.6.1.4 Final PHP Version 4.4.4 mysql 4.1.22 Apache/1.3.37 <?php $id = $_GET['id']; // menu id $pid = $_GET['pid']; //picture id $output= ""; //debug echo $pid; echo "<br/>"; echo $id; // given the menu id we assign description and image path variables as arguments switch ($id) { default: case 55: {return show_img("i/b", "title 1", $pid); }break; case 56: {return show_img("m/b", "title 2", $pid); }break; case 57: {return show_img("g/b", "title 3", $pid); }break; case 58: {return show_img("o/b", "title 4", $pid); }break; case 59: {return show_img("t/b", "title 5", $pid); }break; case 60: {return show_img("d/b", "title 6", $pid); }break; case 61: case 62: case 63: return; break; } //function: insert image given the $pid variable function show_img($imgpath, $desc, $pid) { $pid = $_GET['pid']; $server_root = 'http://'.$_SERVER['SERVER_NAME']; $ins_img = "$server_root/i/$imgpath/$pid.jpg"; //image size $imgsize = @GetImageSize($ins_img); $output .= "<div id=\"big\">"; $output .= "<img src=\"".$ins_img."\" ".$imgsize[3]." alt=\"".$desc."\" />"; $output .= "</div>"; return $output.""; }; ?> Any suggestions? Thank you in advance. Link to comment https://forums.phpfreaks.com/topic/65968-solved-need-help-with-image-gallery-snippet/ Share on other sites More sharing options...
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