Jump to content

[SOLVED] mysql problem


beboo002

Recommended Posts

If these are variables that you are wishing to display together you simply need to

<?php echo $firstname .$age; ?>

 

If you want to concatenate to sql feilds for input into another table or something...

CONCAT('first name', 'age') as nameAge

 

more info would be helpful as to what you have accomplished and what you want

Link to comment
https://forums.phpfreaks.com/topic/66146-solved-mysql-problem/#findComment-330869
Share on other sites

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.