Lamez Posted August 24, 2007 Share Posted August 24, 2007 ok I am getting this error Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /mounted-storage/home48c/sub007/sc33591-LWQU/www/login/members/profile/edit_profile.php on line 49 here is the link: http://lamezz.com/login/members/profile/edit_profile.php?change=password here is my script <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <link rel="stylesheet" type="text/css" href="../../../style/default.css"/> <?php include ("../../../style/include/title.php"); ?> </head> <body> <div class="logo"><?php include ("../../../style/include/header.php"); ?></div> <div class="spacer"></div> <?php include ("../../../style/include/logged_menu_member.php"); ?> <div class="box"> <center><font size="3"> <?php $username = $_COOKIE['loggedin']; if (!isset($_COOKIE['loggedin'])) die("You are not logged in, <a href=../login.php>click here</a> to login."); echo "<b>$username</b>'s Profile"; ?> </font></center></div> <div class="box"><font size="3"> <?php $getlink = $_GET["change"]; if ($getlink == "requestUsername") { echo "Nope"; } elseif ($getlink == "personalDetail") { echo "Not Here Yet"; } elseif ($getlink == "password") { echo "(<form action="update.php" method="post" ><p><u><b>Change your password</b></u><br /></p> //LINE 49 IS HERE!! <center><p> Old Password:<br /> <input type="password" name="oldpass" /> <br /> <br /> New Password: <br /> <input type="password" name="newpass" /> <br /> <br /> </p> <p> <input type="submit" name="Submit" value="Submit" /> </p></center>)"; } else { echo "Error"; } ?> </font></div> <?php include ("../../../style/include/footer.php"); ?> </body> </html> Please Help, Thanks Guys! Link to comment https://forums.phpfreaks.com/topic/66568-solved-parse-error-syntax-error-please-help/ Share on other sites More sharing options...
pocobueno1388 Posted August 24, 2007 Share Posted August 24, 2007 Try this: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <link rel="stylesheet" type="text/css" href="../../../style/default.css"/> <?php include ("../../../style/include/title.php"); ?> </head> <body> <div class="logo"><?php include ("../../../style/include/header.php"); ?></div> <div class="spacer"></div> <?php include ("../../../style/include/logged_menu_member.php"); ?> <div class="box"> <center><font size="3"> <?php $username = $_COOKIE['loggedin']; if (!isset($_COOKIE['loggedin'])) die("You are not logged in, <a href=../login.php>click here</a> to login."); echo "<b>$username</b>'s Profile"; ?> </font></center></div> <div class="box"><font size="3"> <?php $getlink = $_GET["change"]; if ($getlink == "requestUsername") { echo "Nope"; } elseif ($getlink == "personalDetail") { echo "Not Here Yet"; } elseif ($getlink == "password") { print<<<HERE <form action="update.php" method="post" ><p><u><b>Change your password</b></u><br /></p> //LINE 49 IS HERE!! <center><p> Old Password:<br /> <input type="password" name="oldpass" /> <br /> <br /> New Password: <br /> <input type="password" name="newpass" /> <br /> <br /> </p> <p> <input type="submit" name="Submit" value="Submit" /> </p></center> HERE; } else { echo "Error"; } ?> </font></div> <?php include ("../../../style/include/footer.php"); ?> </body> </html> Link to comment https://forums.phpfreaks.com/topic/66568-solved-parse-error-syntax-error-please-help/#findComment-333430 Share on other sites More sharing options...
Lamez Posted August 24, 2007 Author Share Posted August 24, 2007 Thank you so much! Link to comment https://forums.phpfreaks.com/topic/66568-solved-parse-error-syntax-error-please-help/#findComment-333433 Share on other sites More sharing options...
nathanmaxsonadil Posted August 24, 2007 Share Posted August 24, 2007 the problem is echo "(<form action="update.php" method="post" ><p><u><b>Change your password</b></u><br /></p> //LINE 49 IS HERE!! it think that you are ending the line because your are ending the quote change it to echo "(<form action='update.php' method='post' ><p><u><b>Change your password</b></u><br /></p> //LINE 49 IS HERE!! there is probably more places in your code where you have this problem Link to comment https://forums.phpfreaks.com/topic/66568-solved-parse-error-syntax-error-please-help/#findComment-333435 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.