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I have a date in a variable - supposedly formatted properly for MySQL's date field type.  (YYYY-MM-DD).  When I attempt to insert a new record in a table, the date doesn't store properly.

 

$sql = "INSERT INTO `dogs` (`owner_id`, `callname`, `breed`, `sex`, `birthdate`, `height`, `accessid`, `accesstype`) VALUES ($oid, '$nm', '$brd', '$sex', '$dt2snd', '$ht', $aid, '$atyp')";

 

... always ends up with the birthdate field reading '0000-00-00', whether I put quotes on the $dt2snd or not.

 

Any suggestions on what to do or where to 'read up'?

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https://forums.phpfreaks.com/topic/66664-solved-mysql-insert-and-dates/
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you need to define your date before you insert it

$date = date('Y-m-d, H-i-s');

 

It doesn't look like they are wanting that format. Do this instead:

$date = date("Y-m-d");

 

Show us where you give a value to your variable $dt2snd. Also, you need to have single quotes around all your variables in the query.

Plain & simple (to avoid any confusion), $dt2snd is a string.  The string is formatted as 2007-08-25.

 

If I explicitly include a fixed value in a MySQL INSERT statement, the value goes in to the record just fine, but when I reference a variable which is a string formatted exactly the same way, I get 0000-00-00 in the record.

 

The question is, do I need to do anything to a string which is formatted according to the MySQL date 'format' in order to be able to put that variable's value into the record being inserted?

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