Please Help! Checkbox for more dropdowns

[j.g.]

Hi All-

 

I have a page that I want to give the user to add more than one link to... right now the default page has a title and one dropdown for a link:

 

<form name="frm" method="post" action="<?php echo $PHP_SELF;?>">

<INPUT TYPE="HIDDEN" NAME="resource_id" VALUE="<?php echo $resource_id;?>" SIZE="50">

<INPUT TYPE="HIDDEN" NAME="operation" VALUE="<?php echo $operation; ?>">

<INPUT TYPE="HIDDEN" NAME="type_id" VALUE="<?php echo $type_id; ?>">

 

<h1>Add / Update Resources</h1>

 

<table class="box_content" width="80%" border="0" cellpadding="0" cellspacing="0" >

<tbody>

<tr>

  <td class="contentnovertical">

  <div style="padding: 5px;">

  <table border="0" cellpadding="0" cellspacing="5" width="100%">

    <tbody>

    <tr>

      <td>* Title:</td>

      <td><input name="title" value="<?php echo $title; ?>" size="50" type="text"></td>

    </tr>

    <tr>

      <td>

      <span class="plain_sub_head">

        <span class="formlabel">* Link Page:</span>

      </span>

      </td>

      <td>

      <select name="url" onChange="show_offsite()">

        foreach( $urls as $page => $location)
        {
  //echo "<option>loc: ".$location;
 //echo "url: ".$url."</option>";
 echo "<option ";
         if( $url == $location )
{
 echo "SELECTED";
}
echo " VALUE=\"".$location."\">".$page."</OPTION>\n";
       }

      </select>

    </td>

    </tr>

    <tr>

    <td>

      <span id="offsite_label" style="display: none;">Offsite Link:</span>

    </td>

    <td>

      <span id="offsite_text" style="display: none;">

      <input type="text" size="40" maxlength="100" name="offsite_url" value="<?php echo $offsite_url;?>">

      </span>

    </td>

    </tr>

    <tr>

    <td align='center' colspan='2' class="box_heading"> <?php echo $section_heading;?> ( *  - required field )</td>

    </tr>

  </tbody>

  </table>

  </div>

  </td>

</tr>

<tr>

  <td class="contentnovertical">

  <div style="padding-top: 5px; padding-bottom: 5px;" nowrap="" align="center">

    <input type="submit" class="submit_button" value="<?php echo $operation; ?>" >

    <A HREF="resources_updater.php?type_id=<?php echo $type_id;?>"><span class="content_text">Cancel</span></A>

  </div>

  </td>

  </tr>

</tbody>

</table>

</form>

 

<script type="text/javascript">

show_offsite();

function show_offsite()

{

  if (document.frm.url.value == 'offsite')

  {

    document.getElementById("offsite_text").style.display = "inline";

    document.getElementById("offsite_label").style.display = "inline";

  }

  else

  {

    document.getElementById("offsite_text").style.display = "none";

    document.getElementById("offsite_label").style.display = "none";

  }

}

</script>

 

 

What I'd like to do is put a checkbox next to the current dropdown asking 'Add Another Link' -- and if this box is checked, show another dropdown under it....

 

 

All help will be greatly appreciated! So, I need to add the box, and if it is checked, show another dropdown under it.

 

Please let me know if I need to provide any additional information for you to help me solve this problem.

 

Thanks!

-j.g.

[j.g.]

OK, I got the dropdown on the page, now I just need to know how to, IF CHECKED, show another link in another row under it...

 

<tr>

<td>

  <span class="plain_sub_head">

  <span class="formlabel">* Link Page:</span>

  </span>

  </td>

  <td>

  <select name="url" onChange="show_offsite()">

    foreach( $urls as $page => $location)
    {
     //echo "<option>loc: ".$location;
     //echo "url: ".$url."</option>";
     echo "<option ";
	if( $url == $location )
{
 echo "SELECTED";
}
     echo " VALUE=\"".$location."\">".$page."</OPTION>\n";
    }

  </select>

    <input type="checkbox" name="add_link"> Add Another Link

</td>

</tr>

 

 

Thanks much!

-j.g.