LemonInflux Posted August 29, 2007 Share Posted August 29, 2007 Basically, for a small project I'm doing, I wanted a flatfile log in code for entry. So, I set up this. The problem is, in index.htm (the first code), when I press submit, even if the values are right, it just says 'login failed' on login.php (the second code). Here are the codes: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"><style type="text/css"> <!-- body,td,th { font-family: Verdana, Arial, Helvetica, sans-serif; } --> </style></head> <body> <center> <table border="0" cellspacing="5" cellpadding="5"> <form action="login.php" method="POST"> <tr> <td>Username</td> <td><input type="text" size="10" name="f_user"></td> </tr> <tr> <td>Password</td> <td><input type="password" size="10" name="f_pass"></td> </tr> <tr> <td colspan="2" align="center"><input type="submit" name="submit" value="Log In"> </td> </tr> </form> </table> <p>Not a member? (<a href="register.php">register</a>)</p> </center> </body> </html> <?php // authenticate using form variables $status = authenticate($f_user, $f_pass); // if user/pass combination is correct if ($status == 1) { // initiate a session session_start(); // register some session variables session_register("SESSION"); // including the username session_register("SESSION_UNAME"); $SESSION_UNAME = $f_user; // redirect to protected page header("Location: secure_page.php"); exit(); } else // user/pass check failed { // redirect to error page echo "Login failed!"; exit(); } // authenticate username/password against usersdb // returns: -1 if user does not exist // 0 if user exists but password is incorrect // 1 if username and password are correct function authenticate($user, $pass) { $result = -1; // make sure that the script has permission to read this file! $data = file("userdb.txt"); // iterate through file foreach ($data as $line) { $arr = explode(" | ", $line); // if username matches // test password if ($arr[1] == $_POST['f_user']) { // if match, user/pass combination is correct // return 1 if ($arr[2] == md5($_POST['f_pass'])) { $result = 1; break; } // otherwise return 0 else { $result = 0; break; } } } // return value return $result; } ?> Quote Link to comment Share on other sites More sharing options...
LemonInflux Posted August 29, 2007 Author Share Posted August 29, 2007 bump Quote Link to comment Share on other sites More sharing options...
lightningstrike Posted August 29, 2007 Share Posted August 29, 2007 Refrain from using session_register it is deprecated instead use $_SESSION["variablename"] = "value"; Should $arr[1] and $arr[2] be $arr[0] and $arr[1] as after exploding element keys start at 0. If that doesn't fix it, please show us what your userdb file looks like in structure. Quote Link to comment Share on other sites More sharing options...
LemonInflux Posted August 29, 2007 Author Share Posted August 29, 2007 Success! thanks, it was the array thing. Quote Link to comment Share on other sites More sharing options...
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