Asperon Posted September 4, 2007 Share Posted September 4, 2007 here is my code, my png comes with the encrypted data, I know that without html, it would view fine, and I know that <img> from another file would work... but is there another way to create these images in the situation that I have set up? <?php //get coupon info $query2 = "SELECT couponID,startDate,clicks,active,endDate,location FROM coupons WHERE businessID='$bID'"; $result2 = mysql_query($query2) or die('QUery failed: ' . mysql_error()); $rows = mysql_affected_rows(); //coupon print function function printCoupon($loc){ // The file $filename = $loc; $percent = 0.5; // Content type header('Content-type: image/png'); // Get new dimensions list($width, $height) = getimagesize($filename); $new_width = $width * $percent; $new_height = $height * $percent; // Resample $image_p = imagecreatetruecolor($new_width, $new_height); $image = imagecreatefromjpeg($filename); imagecopyresampled($image_p, $image, 0, 0, 0, 0, $new_width, $new_height, $width, $height); // Output imagepng($image_p); } // Printing results in HTML echo "<p> </p>"; echo "<table border='1' align='center'>\n"; echo "<tr align='center'>\n"; echo "<td>Coupon ID</td>\n"; echo "<td>Creation Date</td>\n"; echo "<td>Clicks</td>\n"; echo "<td>Active</td>\n"; echo "<td>End Date</td>\n"; echo "<td>Coupon</td>\n"; for($i=0; $i <= $rows-1; $i++){ echo "<tr align='center'>\n"; echo "<td>" . mysql_result($result2,$i,'couponID') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'startDate') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'clicks') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'active') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'endDate') . "</td>\n"; echo "<td>" . printCoupon(mysql_result($result2,$i,'location')) . "</td>\n"; echo "\t</tr>\n"; } echo "</table>\n"; ?> Link to comment https://forums.phpfreaks.com/topic/67955-solved-gd-resampling/ Share on other sites More sharing options...
Asperon Posted September 4, 2007 Author Share Posted September 4, 2007 I figured it out..here's my code <?php //get coupon info $query2 = "SELECT couponID,startDate,clicks,active,endDate,location FROM coupons WHERE businessID='$bID'"; $result2 = mysql_query($query2) or die('Query failed: ' . mysql_error()); $rows = mysql_affected_rows(); // Printing results in HTML echo "<p> </p>"; echo "<table border='1' align='center'>\n"; echo "<tr align='center'>\n"; echo "<td>Coupon ID</td>\n"; echo "<td>Creation Date</td>\n"; echo "<td>Clicks</td>\n"; echo "<td>Active</td>\n"; echo "<td>End Date</td>\n"; echo "<td>Coupon</td>\n"; for($i=0; $i <= $rows-1; $i++){ $loc = mysql_result($result2,$i,'location'); $dim = getimagesize($loc); $width = $dim[0]*.5; $height= $dim[1]*.5; echo "<tr align='center'>\n"; echo "<td>" . mysql_result($result2,$i,'couponID') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'startDate') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'clicks') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'active') . "</td>\n"; echo "<td>" . mysql_result($result2,$i,'endDate') . "</td>\n"; echo "<td><img src='$loc' width=$width height=$height></img></td>\n"; echo "\t</tr>\n"; ImageDestroy($image_p); } echo "</table>\n"; ?> Link to comment https://forums.phpfreaks.com/topic/67955-solved-gd-resampling/#findComment-341569 Share on other sites More sharing options...
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