[SOLVED] Password Combination

[cashflowtips]

im looking for solution on how to check the password combination...

 

here is the example: -

 

$text = "onlyalphanumericcharacters012345";

if (ereg('[^A-Za-z0-9]', $text)) {
  echo "This contains characters other than letters and numbers";
}
else {
  echo "This contains only letters and numbers";    
}

 

but the problem here is - i want the code only accept with these kind of combination: -

 

a) alphabet + number

b) alphabet + symbol

c) number + symbol

 

can anyone help me? thanks alot

 

[btherl]

How do you define "symbol" ?  Everything visible on the keyboard that is not alpha or numeric?

[phat_hip_prog]

You might like to have a look at this...

http://www.linuxquestions.org/questions/showthread.php?t=521792

which links to...

http://www.owasp.org/index.php/OWASP_PHP_Filters

[cashflowtips]

How do you define "symbol" ?  Everything visible on the keyboard that is not alpha or numeric?

 

yes, anything!

[cashflowtips]

maybe my question is not very clear and i want to apologize for that... let me explain once again...

 

what i really want is the code that can check where the input must have

 

a) must have Alphabet + must have Number (if the input only one of these two, it will return false)

b) must have Alphabet + must have Symbol (the condition same as A(above))

c) must have Number + must have Symbol (the condition same as A(above))

 

as for the Symbol, im not sure what is the basic one that usually been used by other website but i know some of them accept symbol as password characters to increase security (hard for hacker to guess the password)

[btherl]

Are you checking for "at least one alpha" and "at least one number" ?  So these would be valid:

 

Nt4%

NN99

55%%aa

qwer!@#$

 

But these would be invalid

abcd

1234

!@#$

 

because they only contain one class of characters

[cashflowtips]

Are you checking for "at least one alpha" and "at least one number" ?  So these would be valid:

 

Nt4%

NN99

55%%aa

qwer!@#$

 

But these would be invalid

abcd

1234

!@#$

 

because they only contain one class of characters

 

exactly... thanks for more clear view on the question... can u help me with this

[btherl]

Ok, some of that is easy:

 

$got_alpha = preg_match('|[A-Za-z]|', $password);
$got_num = preg_match('|[0-9]|', $password);

 

But as for the symbols.. there are four groups of symbols in the ascii table

 

$got_symbol = preg_match('|[ -/:-@[-`{-~]|', $password);

 

That oughta work.  After that you just need to check

 

if (($got_alpha && $got_num) || ($got_alpha && $got_symbol) || $got_num && $got_symbol))

[cashflowtips]

thanks you so much