Sallie_ann Posted July 9, 2003 Share Posted July 9, 2003 Hi... I have connected to a MySQL database that contains information on various companies. I have created a HTML form with 4 drop down list boxes that have static information to (hopefully) search the database including company size, location, sector, etc. The user will select items from the drop down list boxes and click go to retrieve the required data. For example, a user may want to search for all medium sized companies in Leicester in the IT sector. The PHP code I have so far is as follows; mysql_select_db(\"beacon\",$db); if($_POST[\'company_size\'] == 1) $where = \'company_size BETWEEN 1 AND 9\'; if($_POST[\'company_size\'] == 2) $where = \'company_size BETWEEN 10 AND 49\'; if($_POST[\'company_size\'] == 3) $where = \'company_size BETWEEN 50 AND 250\'; if($_POST[\'County\'] == 1) $where1 = \'County LIKE Derbyshire\'; if($_POST[\'County\'] == 2) $where1 = \'County LIKE Leicestershire\'; if($_POST[\'County\'] == 3) $where1 = \'County LIKE Lincolnshire\'; if($_POST[\'County\'] == 4) $where1 = \'County LIKE Northants\'; if($_POST[\'County\'] == 5) $where1 = \'County LIKE Nottinghamshire\'; $result = mysql_query(\"SELECT name, County, sector, company_size \" . \"FROM beacon \" . \"WHERE\". $where .\"AND\". $where1); echo \"<table border=1 align=center>n\"; echo \"<tr><td>Name</td><td>County</td><td>Sector</td><td>Company Size</td></tr>n\"; while ($myrow = mysql_query($query)) { printf(\"<tr><td>%s</td><td>%s</td><td>%s</td><td>%s</td></tr>n\", $myrow[0], $myrow[1], $myrow[2], $myrow[3]); } echo \"</table>n\"; An example of my HTML drop down list code is as follows; <select name=\"company_size\"> <option value=\"0\" selected>Select Company Size</option> <option value=\"1\">1 - 9</option> <option value=\"2\">10 - 49</option> <option value=\"3\">50 - 250</option> </select> No data is being output from the database except the table column headings. I managed to output all the database data in the table before I entered the query so I know the problem lies here. Any help would be really appreciated. Sallie-ann Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/ Share on other sites More sharing options...
shivabharat Posted July 9, 2003 Share Posted July 9, 2003 The problme is in query ur query should be like $where = \'company_size BETWEEN 1 AND 9\'; $where1 = \'County LIKE \'Leicestershire%\' \'; $result = mysql_query(\"SELECT name, County, sector, company_size FROM beacon WHERE. $where .\"AND\". $where1) or die(\"Problem\"); Remember ur LIKE synatx should be this way select * from table where name LIKE \'php\' or select * from table where name LIKE \'%php\' use the die statement to see if ur query is working properly Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2274 Share on other sites More sharing options...
Sallie_ann Posted July 9, 2003 Author Share Posted July 9, 2003 Thanks for your help, my queries now read as follows; mysql_select_db(\"beacon\",$db); if($_POST[\'company_size\'] == 1) $where = \'company_size BETWEEN 1 AND 9\'; if($_POST[\'company_size\'] == 2) $where = \'company_size BETWEEN 10 AND 49\'; if($_POST[\'company_size\'] == 3) $where = \'company_size BETWEEN 50 AND 250\'; if($_POST[\'County\'] == 1) $where1 = \'County LIKE \'Derbyshire%\' \'; if($_POST[\'County\'] == 2) $where1 = \'County LIKE \'Leicestershire%\' \'; if($_POST[\'County\'] == 3) $where1 = \'County LIKE \'Lincolnshire%\' \'; if($_POST[\'County\'] == 4) $where1 = \'County LIKE \'Northants%\' \'; if($_POST[\'County\'] == 5) $where1 = \'County LIKE \'Nottinghamshire%\' \'; $result = mysql_query(\"SELECT name, County, sector, company_size FROM beacon WHERE. $where .\"AND\". $where1) or die(\"Problem\"); echo \"<table border=1 align=center>n\"; echo \"<tr><td>Name</td><td>County</td><td>Sector</td><td>Company Size</td></tr>n\"; while ($myrow = mysql_query($query)) { printf(\"<tr><td>%s</td><td>%s</td><td>%s</td><td>%s</td></tr>n\", $myrow[0], $myrow[1], $myrow[2], $myrow[3]); } echo \"</table>n\"; I am being given the following error message referring to the first echo. \"Parse error: parse error, unexpected T_STRING\" And I\'m unsure why! Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2275 Share on other sites More sharing options...
Sallie_ann Posted July 9, 2003 Author Share Posted July 9, 2003 And I am now also getting error messages for the first line of my query $where1 = \'County LIKE \'Derbyshire%\' \'; :oops: Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2276 Share on other sites More sharing options...
gizmola Posted July 9, 2003 Share Posted July 9, 2003 And I am now also getting error messages for the first line of my query $where1 = \'County LIKE \'Derbyshire%\' \'; :oops: It\'s your quotes. Switch to $where1 = \"County LIKE \'Derbyshire%\'\"; Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2277 Share on other sites More sharing options...
Sallie_ann Posted July 9, 2003 Author Share Posted July 9, 2003 I have changed my WHERE statements as you suggested and am now being given error messages for the final line in the following extract of code. :? if($_POST[\'County\'] == 1) $where1 = \"County LIKE \'Derbyshire%\'\"; if($_POST[\'County\'] == 2) $where1 = \"County LIKE \'Leicestershire%\'\"; if($_POST[\'County\'] == 3) $where1 = \"County LIKE \'Lincolnshire%\'\"; if($_POST[\'County\'] == 4) $where1 = \"County LIKE \'Northants%\'\"; if($_POST[\'County\'] == 5) $where1 = \"County LIKE \'Nottinghamshire%\'\"; $result = mysql_query(\"SELECT name, County, sector, company_size FROM beacon WHERE. $where .\"AND\". $where1) or die(\"Problem\"); Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2278 Share on other sites More sharing options...
shivabharat Posted July 9, 2003 Share Posted July 9, 2003 Try this $result = mysql_query("SELECT name, County, sector, company_size FROM beacon WHERE". $where ."AND". $where1) or die("Problem"); Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2279 Share on other sites More sharing options...
Sallie_ann Posted July 9, 2003 Author Share Posted July 9, 2003 It is now outputting \"Problem\". My complete code is now as follows; mysql_select_db(\"beacon\",$db); if($_POST[\'company_size\'] == 1) $where = \'company_size BETWEEN 1 AND 9\'; if($_POST[\'company_size\'] == 2) $where = \'company_size BETWEEN 10 AND 49\'; if($_POST[\'company_size\'] == 3) $where = \'company_size BETWEEN 50 AND 250\'; if($_POST[\'County\'] == 1) $where1 = \"County LIKE \'Derbyshire%\'\"; if($_POST[\'County\'] == 2) $where1 = \"County LIKE \'Leicestershire%\'\"; if($_POST[\'County\'] == 3) $where1 = \"County LIKE \'Lincolnshire%\'\"; if($_POST[\'County\'] == 4) $where1 = \"County LIKE \'Northants%\'\"; if($_POST[\'County\'] == 5) $where1 = \"County LIKE \'Nottinghamshire%\'\"; $result = mysql_query(\"SELECT name, County, sector, company_size FROM beacon WHERE\". $where .\"AND\". $where1) or die(\"Problem\"); echo \"<table border=1 align=center>n\"; echo \"<tr><td>Name</td><td>County</td><td>Sector</td><td>Company Size</td></tr>n\"; while ($myrow = mysql_query($query)) { printf(\"<tr><td>%s</td><td>%s</td><td>%s</td><td>%s</td></tr>n\", $myrow[0], $myrow[1], $myrow[2], $myrow[3]); } echo \"</table>n\"; Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2281 Share on other sites More sharing options...
shivabharat Posted July 9, 2003 Share Posted July 9, 2003 As a suggestion Try this echo $sql which will be the query now execute the query separtely and see if u are getting the desired output. $sql = "SELECT name, County, sector, company_size FROM beacon WHERE". $where ."AND". $where1; echo $sql; $result = mysql_query($sql) or die("Problem"); Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2282 Share on other sites More sharing options...
Sallie_ann Posted July 9, 2003 Author Share Posted July 9, 2003 It is now outputting; SELECT name, County, sector, company_size FROM beacon WHEREcompany_size BETWEEN 1 AND 9ANDProblem Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2283 Share on other sites More sharing options...
shivabharat Posted July 9, 2003 Share Posted July 9, 2003 I guess what is being displayed is not the complete query is that so? SELECT name, County, sector, company_size FROM beacon WHEREcompany_size BETWEEN 1 AND 9 AND County LIKE \'Leicestershire%\' See that u send the correct value and alos I see there is no space \"BETWEEN 1 AND 9AND\" so u have to add a space inbetween Quote Link to comment https://forums.phpfreaks.com/topic/689-mysql-query-output-problems/#findComment-2284 Share on other sites More sharing options...
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