DarkPrince2005 Posted September 12, 2007 Share Posted September 12, 2007 Does anybody know of a script where I can calcullate a datediff and make a pop-up apear a week before a certain date Link to comment https://forums.phpfreaks.com/topic/68975-notification/ Share on other sites More sharing options...
jitesh Posted September 12, 2007 Share Posted September 12, 2007 Date Diff <?php $date1 = "2007-12-12"; $date2 = "2007-12-06"; echo (strtotime($date1) - strtotime($date2))/(60*60*24) ." Days"; ?> Previous week <?php $date1 = "2007-12-12"; echo date("Y-m-d",mktime(0,0,0,12,12-7,2007)); ?> Link to comment https://forums.phpfreaks.com/topic/68975-notification/#findComment-346728 Share on other sites More sharing options...
DarkPrince2005 Posted November 12, 2007 Author Share Posted November 12, 2007 how can i retrieve a date from a table and set it to $date1's value and the curdate() to date2's value, cause everything I'm trying isn't working <?php ini_set('display_errors','On'); error_reporting(E_ALL); mysql_connect("localhost","root",""); mysql_select_db("database"); $r=mysql_query("select [i]field[/i] from [i]table[/i] where Employee_Firstname like 'KS'"); $date2 ="$r"; $date1 = "curdate()"; echo (strtotime($date1) - strtotime($date2))/(60*60*24) ." Days"; ?> Link to comment https://forums.phpfreaks.com/topic/68975-notification/#findComment-389741 Share on other sites More sharing options...
aschk Posted November 12, 2007 Share Posted November 12, 2007 You might want to try using mysql_fetch_assoc or that $r (result) handle. e.g. $r=mysql_query("select [i]field[/i] from [i]table[/i] where Employee_Firstname like 'KS'"); $row = mysql_fetch_assoc($r); $date2 = $r['field']; $date1 = "curdate()"; Link to comment https://forums.phpfreaks.com/topic/68975-notification/#findComment-389743 Share on other sites More sharing options...
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