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Nesting an in/else within an if/else.. Is it my answer?


BadGoat

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Hello!

 

Looking for a kick in the right direction...  How would I go about nesting an if/else within an if/else? As an example, let's say I have a list of music groups, and by clicking one of them, a list of their albums is displayed. (this part I can do!) But I want a list of the songs associated with that album to be displayed below the album. Perhaps nesting an if/else within an if/else is not the answer?  I have tinkered with some theoretical code, and the only time I have been able to return anything, it's a single wrong song in every other album list. Any help would be most appreciated.

 

Here's a bit of code which I've successfully used to

 

 

    $sqlquery = "SELECT song.*, album.*group.* FROM song, album, group WHERE song.song_id = album.song_id AND album.group_id = group.group_id AND group.group_id = '$group_id' ";
    $queryresult = mysql_query($sqlquery) or die(" Could not execute mysql query !");
    $row = mysql_fetch_row($queryresult);

    $album= $row[0];
    $tdcount = 1;
    $numtd = 1; // number of cells per row
    echo '

      ';
   mysql_data_seek($queryresult,0)  ;
while($row = mysql_fetch_array($queryresult)) {

    if ($tdcount == 1)
echo ''.$row['album'],' ';
if ($tdcount == $numtd) {
echo "<br />";
$tdcount = 1;
} else {
$tdcount++;
}
}

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So guess you have structure like

[pre]

group            album              song

----------        -----------        -----------

group_id  --+    album_id  --+    song_id

group      |    album        |    song

            +--<  group_id    +---< album_id

[/pre]

 

<?php
$sql = "SELECT a.album, s.song
        FROM song s 
            INNER JOIN album a ON s.album_id = a.album_id
            INNER JOIN group g ON a.group_id = g.group_id
        WHERE group_id = '$group_id'
        ORDER BY album, song";
$res = mysql_query($sql) or die (mysql_error()."<p>$sql</p>");

$lastAlbum = '';
while (list($album, $song) = mysql_fetch_row($res))
{
    if ($lastAlbum != $album)
    {
        echo "<h3>$album</h3>";
        $lastAlbum = $album;
    }
    echo "$song <br />";
}

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