AngN Posted September 13, 2007 Share Posted September 13, 2007 Hi, using PHP how can I show the results of a SQL query to look like this:- Name Address Delete Y/N Someone Somewhere Remove Code sample:- // Fetch each database table row of the results while($row = @ mysql_fetch_array($result)) { echo ("<p>" . $row["job_id"] ). ( $row["title"] ). ( $row["employer"] ) . ( $row["start_date"] ). ( $row["salary"] ) . ( $row["req_exp"] ) . ( $row["req_skills"] ) . ( $row["description"] ) . ( $row["remove"] ); } Also how can I make the word 'remove' link to another PHP file? I would be grateful for any help Quote Link to comment Share on other sites More sharing options...
recklessgeneral Posted September 13, 2007 Share Posted September 13, 2007 Hi, You would use a HTML table, with the first row containing <th> elements for the headings, then use your while loop to extract the data. Each iteration of the loop would be in a <tr> and each item would be in a <td></td> pair of tags: <table> <tr> <th>Name</th> <th>Address</th> <th>Delete Y/N</th> </tr> <?php // Fetch each database table row of the results while($row = @ mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['address'] ."</td>"; echo "<td><a href=\"remove.php?id=" . $row['job_id'] . "\">Remove</a></td>"; echo "</tr>"; } ?> </table> The 'Remove' has been made into a link using the <a> tags, and links to a page named remove.php. The '?id=...' part allows the chosen job to be passed through to the remove.php page, which can then be obtained using $_GET['id']. Hope this helps, Darren. Quote Link to comment Share on other sites More sharing options...
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