bri4n Posted September 13, 2007 Share Posted September 13, 2007 Hi everyone! I have a page that has 10 rows appear on it, but I also want 4 columns (not just 1). I was wondering if someone could tell me how I can go about and get 4 columns and 10 rows to appear on each page. Here is the code below: <?php include("include/assorted.inc.php"); /*Connect to database*/ $connection=mysql_connect($host,$user,$password) or die("Could not connect to the server"); $db=mysql_select_db($database,$connection) or die("Could not connect to the database"); //This checks to see if there is a page number. If not, it will set it to page 1 if (!(isset($pagenum))) { $pagenum = 1; } //Here we count the number of results //Edit $data to be your query $data = mysql_query("SELECT firstname,lastname FROM userinfo") or die(mysql_error()); $rows = mysql_num_rows($data); //This is the number of results displayed per page $page_rows = 10; //This tells us the page number of our last page $last = ceil($rows/$page_rows); //this makes sure the page number isn't below one, or more than our maximum pages if ($pagenum < 1) { $pagenum = 1; } elseif ($pagenum > $last) { $pagenum = $last; } //This sets the range to display in our query $max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows; //This is your query again, the same one... the only difference is we add $max into it $data_p = mysql_query("SELECT firstname,lastnameFROM userinfo $max ") or die(mysql_error()); //This is where you display your query results while($info = mysql_fetch_array( $data_p )) { Print $info['firstname']. ' '.$info['lastname']; echo "<br>"; } echo "<p>"; // This shows the user what page they are on, and the total number of pages echo " --Page $pagenum of $last-- <p>"; // First we check if we are on page one. If we are then we don't need a link to the previous page or the first page so we do nothing. If we aren't then we generate links to the first page, and to the previous page. if ($pagenum == 1) { } else { echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1'> <<-First</a> "; echo " "; $previous = $pagenum-1; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous'> <-Previous</a> "; } //just a spacer echo " ---- "; //This does the same as above, only checking if we are on the last page, and then generating the Next and Last links if ($pagenum == $last) { } else { $next = $pagenum+1; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next'>Next -></a> "; echo " "; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last'>Last ->></a> "; } ?> Thanks for any help and pointers!! Brian Quote Link to comment https://forums.phpfreaks.com/topic/69169-pagination-question/ Share on other sites More sharing options...
sasa Posted September 13, 2007 Share Posted September 13, 2007 change line $page_rows = 10; to $page_rows = 40; and part //This is where you display your query results while($info = mysql_fetch_array( $data_p )) { Print $info['firstname']. ' '.$info['lastname']; echo " "; } echo "<p>"; to //This is where you display your query results echo '<table>'; $i = 0; while($info = mysql_fetch_array( $data_p )) { if($i % 4 == 0) echo '<tr>'; Print '<td>'. $info['firstname']. ' '. $info['lastname']. '</td>'; echo " "; if(++$i % 4 == 0) echo '</tr>'; } if($i % 4 != 0) echo '</tr>'; echo '</table>'; //echo "<p>"; Quote Link to comment https://forums.phpfreaks.com/topic/69169-pagination-question/#findComment-347822 Share on other sites More sharing options...
bri4n Posted September 14, 2007 Author Share Posted September 14, 2007 Hi sasa! Thanks for your help, that got it! Many thanks, Brian Quote Link to comment https://forums.phpfreaks.com/topic/69169-pagination-question/#findComment-348209 Share on other sites More sharing options...
maxudaskin Posted September 14, 2007 Share Posted September 14, 2007 Mark TOPIC SOLVED Quote Link to comment https://forums.phpfreaks.com/topic/69169-pagination-question/#findComment-348211 Share on other sites More sharing options...
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