redyard Posted September 13, 2007 Share Posted September 13, 2007 Hi all, I've been working through php codeto connect to Google checkout, the code is supplied by http://www.phpgcheckout.com/ Through out the code there is the use of @param within comments but the @param is colored as if it's not commented out (I'm using textmate so it's colored dark blue). Is this @param importanat to the code or is it part of the commenting. I'm asking because I wanted to reorganise the code by deleting returns and white space so I can read it easier. /** * Builds Google Checkout Button Constructor * * @param unknown_type $gCart * @param unknown_type $size * @param unknown_type $style * @param unknown_type $variant * @return gButton */ Thanks c. Link to comment https://forums.phpfreaks.com/topic/69205-param/ Share on other sites More sharing options...
GingerRobot Posted September 13, 2007 Share Posted September 13, 2007 Anything that is between the /* and */ will be commented out - you don't need to worry, there is no code that is executed. Im not entirely sure why they have placed the @ sign in the comments; perhaps it was for the developers. As for why it appears coloured, ive never used that particular application so i cannot be sure, but i would guess that it highlights anything where you suppress errors. The @ symbol is used to ignore errors on a single line. Link to comment https://forums.phpfreaks.com/topic/69205-param/#findComment-347836 Share on other sites More sharing options...
wildteen88 Posted September 13, 2007 Share Posted September 13, 2007 That has nothing to do with PHP. PHP ignores all text between /* and */ or after // or # . However it does have something to do with third apps such as phpDoc which can process comments to create documentation for a specific function/class or block of code within a script. Link to comment https://forums.phpfreaks.com/topic/69205-param/#findComment-347853 Share on other sites More sharing options...
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