some help

[adv]

hello

 

i wanna made a form that has the year

but i don`t wanna make it with list

i want them to put the year instead like : 07 ,, 08

how do i do it in php to give error if they put something else

 

something like this

 

 

$ar = array("07","08","09","10");

 

foreach ($ar as $year)

etc etc

 

i think something like that

thanks in advance

 

 

 

[GingerRobot]

Well, if you did want to just check against a list of possible values, you could use the in_array() function.

 

However, it would probably be easier to treat the input as a number, and just check it is within whatever parameters you want.

[adv]

can u give me an example please

i dont quite understand

[AV1611]

you want them to enter year into a box or select it from a pulldown?

(pull down is better)

If they type in the year, you have to verify it's a valid year OR verify that year exists in the database as written.

 

Pulldown created dynamically

(select distinct year from table order by year asc...)

seems the best to me, not knowing what you are looking for...

[adv]

AV yes i want them to type it down not box

i know with box

 

is there a function that can do this

or something simillary

please  help

 

have  last 2 digits of year "07" "08" "09"

and if they type something else it must give error

 

[AV1611]

AV yes i want them to type it down not box

i know with box

 

Sorry, I'm not able to understand what you just said

 

do you

A. want pulldown boxes

B. want them to type the data into a text field

 

 

[adv]

AV : B

 

but when someone types something else then "07" "08" "09"  I  want to show an error message

 

how do i check in the field box that??

hope you understand now :|

 

[AV1611]

Well, I would allow them to enter from 1 to 4 digits (regex to verify they are numbers only)

then maybe pad left with 0's if the string length = 1

then set

$variable=subst($whatever,-2,2)

 

and that would always give you a number with leading 0 if they only put a "7" which lazy people like me do

[AV1611]

$variable=subst($whatever,-2,2)

before I get corrected...

$variable=subst($whatever,-2)

 

would be adequate