[SOLVED] Output database entries in a table

[couplebb]

I'm trying to display the entries in a table of two columns, one entry per table cell - in other words, two entries per row, number of rows based on number of entries in the database. But it still doesn't seem to work. It displays one entry per row... I don't know where the problem is. Here's my code:

 

echo "<table width='490' border='0' cellspacing='10' cellpadding='10'>";

$num = mysql_num_rows($result);

$numrows = round($num/2);

while ($row=mysql_fetch_array($result))

{

extract($row);

$count=1;

while ($count<$numrows){

echo "<tr>";

$count2=0;

while($count2<1){

echo "<td width='245' align='center' valign='top'><span class='content2 style2'>";

echo "<img src='$picaddy' alt='$firstname $lastname'><br>$lastname<br>$firstname</span></td>";

$count2=$count2+1;

}

$count=$count+1;

echo "</tr>";

}

}

echo "</table>";

 

[tr33b1rd]

Try this. You don't need to know the number of rows, "while ($row=mysql_fetch_array($result))" will loop through every row selected. Unless there is another part that I'm not seeing. You only have 1 column in your table, if you want to have a multi column table you will have to throw in some <td></td> tags.

 

echo "<table width='490' border='0' cellspacing='10' cellpadding='10'>";
$query = mysql_query(YOUR QUERY);
while ($array = mysql_fetch_array($query)){
   $firstname = $array["firstname"];
   $lastname = $array["lastname"];
  echo("<tr><td width='245' align='center' valign='top' class='content2 style2'><img src='".$picaddy."' alt='".$firstname." ".$lastname."'>".$lastname." ".$firstname."</td></tr>");
} 
echo "</table>";

[sasa]

try

echo "<table width='490' border='0' cellspacing='10' cellpadding='10'>";
//$num = mysql_num_rows($result);
//$numrows = round($num/2);
while ($row=mysql_fetch_array($result))
{
extract($row);
//$count=1;
//while ($count<$numrows){
echo "<tr>";
//$count2=0;
//while($count2<1){
echo "<td width='245' align='center' valign='top'><span class='content2 style2'>";
echo "<img src='$picaddy' alt='$firstname $lastname'> $lastname $firstname</span></td>";
//$count2=$count2+1;
if ($row = mysql_fetch_array($result)){
	extract($row);
	echo "<td width='245' align='center' valign='top'><span class='content2 style2'>";
	echo "<img src='$picaddy' alt='$firstname $lastname'> $lastname $firstname</span></td>";
} else echo '<td> </td>';
//}
//$count=$count+1;
echo "</tr>";
//}
}
echo "</table>";

[dbo]

Here's a more general example. P.S. I like using for loops when I can. I guess I'm too structured, lol.

 

function printTable($mysql_result)
{
   echo "<table>\n";
   $fields = mysql_num_fields($mysql_result);
   $rows = mysql_num_rows($mysql_result);
   for( $i = 0; $i < $rows; ++$i )
   {
      echo "<tr>\n";
      $row = mysql_fetch_row($mysql_result);
      for( $j = 0; $j < $fields; ++$j )
      {
         echo "<td>" . $row[$j] . "</td>\n";
      }
      echo "</tr>\n";
   }
   echo "</table>\n";
}

 

So then usage would be something like:

 

$result = mysql_query("SELECT * FROM table");
printTable($result);

[couplebb]

Thank you everyone! It works great!