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Select, Where, If, Else Statement Question


Sallie_ann

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Hi,

 

I am trying to create a select statement that will extract data from a MySQL database when the user selects a number of options from 4 drop down list boxes.

 

Here is my code for $where1 (there are 4 in total).

 

 

switch($_POST[\'company_size\'])

{

case 1:

$where1 = \"company_size LIKE \'Small\'\";

break;

case 2:

$where1 = \"company_size LIKE \'Medium\'\";

break;

case 3:

$where1 = \"company_size LIKE \'Large\'\";

break;

default:

break;

}

 

 

This all works fine but I am not sure how to construct the where clause so that only one or up to all four options can be selected from the options.

 

 

$whereclause = $where1;

 

if($whereclause == \"\")

{

$whereclause = $where2;

}

else

{

if($whereclause2 == \"\")

{

$whereclause = $where3;

}

else

{

if($whereclause3 == \"\")

{

$whereclause = $where4;

}

else

{

 

if($where4 != \"\")

{

$whereclause .= \" AND \" . $where2 .= \" AND \" . $where3 .= \" AND \" . $where4;

}

}

 

if($whereclause != \"\")

{

$whereclause = \" WHERE \" . $whereclause;

}

 

$sql = \"SELECT name, County, sector, company_size

FROM beacon

$whereclause\";

 

 

Anybody able to help?!

Link to comment
https://forums.phpfreaks.com/topic/700-select-where-if-else-statement-question/
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Try something like...

 

[php:1:857bb6e23d]switch($_POST[\'company_size\'])

{

case 1:

$where1 = \"Small\";

break;

case 2:

$where1 = \"Medium\";

break;

case 3:

$where1 = \"Large\";

break;

default:

break;

}

 

$query = \"SELECT name, County, sector, company_size FROM beacon WHERE itemhere LIKE $where1\";[/php:1:857bb6e23d]

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