tibberous Posted September 28, 2007 Share Posted September 28, 2007 I have a table called visitors, and the visitors have different codes. I need to see what percentage have the code 5. Right now I am using: return mysql_num_rows(mysql_query("select code from visitors where code='5'")) / mysql_num_rows(mysql_query("select code from visitors")); But it doesn't seem to work. Does anyone know how else to do this? Link to comment https://forums.phpfreaks.com/topic/71105-seeing-what-percent-of-users-in-a-database-have-the-code-5/ Share on other sites More sharing options...
Barand Posted September 28, 2007 Share Posted September 28, 2007 $res = mysql_query ("SELECT SUM(IF(code=5,1,0)) as fives, COUNT(*) as total FROM visitors"); $percent = mysql_result($res,0,'fives') * 100 / mysql_result($res,0,'total'); Link to comment https://forums.phpfreaks.com/topic/71105-seeing-what-percent-of-users-in-a-database-have-the-code-5/#findComment-357581 Share on other sites More sharing options...
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