[SOLVED] Show/Hide True/False

[verdrm]

Can anyone tell me the context in which to use PHP like this:

 

$show_calendar = false;

 

I would like to hide a function if it is set to "false" or show it if it is set to "true".

[Wuhtzu]

<?php

//This could be set by the user through a form or something
$show_calendar = false;

//Determine whether or not to show the calendar
if($show_calendar) {

    //Code to show the calendar

}

?>

[shocker-z]

you could use it like this

 

 

function calendarfunction($true_or_false) {
  if ($true_or_false == true) {
      echo 'Calandar is active';
  } else {
      echo 'Calandar is inactive';
  }
}

$show_calendar = false;

calendarfunction($show_calendar);

 

 

 

If that is what you ment?

 

Regards

Liam

[teng84]

simple and short

 

$calendar = ($condition == true)? showfuctioncalendar($etc):'';

 

i guess hide function is no good but i guess what you mean is call function when needed

 

[verdrm]

Thanks. I worked it out.

 

Now my question is this. I have a form that can update the database with the user's choice (either 'true' or 'false').

 

Example: $showcalendar = true;

 

Is there a way to replace "true" above with a statement that can interact with MySQL and find out whether they chose TRUE or FALSE? So if the user chose "false" it wouldn't show up?

[teng84]

simply over write it

 

select * from table where etc....

then considering you have a result

 

if ($result[selection]== false){

$showcalendar = false;

}

$calendar = ($condition == true)? showfuctioncalendar($etc):'';

[verdrm]

I would like to do it this way, if possible:

 

$show = mysql_query("SELECT choice FROM calendar WHERE dom_id = '$domain_id' ");

$showcalendar = $show; <-- THIS VALUE, if true, would show calendar...$show needs to be able to be replaced with TRUE or FALSE

 

//Determine whether or not to show the calendar

if($showcalendar == true) {

 

The problem that I am having is how do I query MySQL to deliver that value and replace "$show" with that value?

[teng84]

maybe

$show = $_POST['value'];//i dont know if you have post but this might be good sample
$query = "SELECT choice FROM calendar WHERE dom_id = '$domain_id' ";
$result=mysql_query($query);
if ($result){
	$value = mysql_fetch_array($result);
if ($show ==  $value['choice']){
//just show calendar base on the query 
}
else{
	mysql_query('update calendar set  choice = "$show" where yourcondition');
	//show calendar based on the users post
}
}

[verdrm]

I think what I'm looking for is a bit less complicated. Basically I just want to query the column "choice", and if that column has the value "false" it should not show the calendar. If the value is "true", then it should. The problem I am having is in BOLD. I can SELECT the choice from the database, but how do I replace $value with that choice?

 

$value = MySQL SELECT statement here....

 

$showcalendar = $value; 

 

//Determine whether or not to show the calendar

if($showcalendar == true) {

[verdrm]

Nevermind. I figured it out.