[SOLVED] strtotime problem

[mhaey]

hi.. im having some problem regarding strtotime and date function.. i want to find the difference between two dates using strtotime.. and then use the difference in loop to determine the dates between the two given dates... but instead of year 2007.. the output year is 2001.. how come? here's my code..

 

<?

$startDate="01/01/2007";

$endDate="01/08/2007";

 

$days = (strtotime($endDate) - strtotime($startDate)) / 86400 +1;

 

for ($wd = 0; $wd < $days; $wd++)

{

  $weekdays = date(mktime(0, 0, 0, date($startDate)  , date($startDate)+$wd, date($startDate)));

  echo '<br>'.date("d-m-Y",$weekdays);

}

?>

 

and here is my output...

 

01/01/2007

01/08/2007

 

01-01-2001

02-01-2001

03-01-2001

04-01-2001

05-01-2001

06-01-2001

07-01-2001

08-01-2001

 

help.. anyone..

[mhaey]

uhmm.. i know im a noob.. but i really need an answer why the year is 2001..  ??? it might not be the strtotime.. when i check my date("mdy",strtotime("now")); it returns the right date... what should be the problem here...  ???

[sKunKbad]

I'm playing around with it, but can't promise anything. I'll post if I figure it out.

[mhaey]

I'm playing around with it, but can't promise anything. I'll post if I figure it out.

 

thank you

[sKunKbad]

<?php
$startDate="01/01/2007";
$endDate="01/08/2007";
$startD = strtotime($startDate);
$endD = strtotime($endDate);
$diffSeconds = $endD - $startD;
$days = ($diffSeconds / 86400);
for ($wd = 1; $wd < $days; $wd++)
{
	$weekdays = ($startD + 86400*($wd));
	echo date("d-m-Y",$weekdays) . "<br />";
}
?>

 

If you want the difference to include the first day, then change the for loop to $wd = 0.

[mhaey]

<?php
$startDate="01/01/2007";
$endDate="01/08/2007";
$startD = strtotime($startDate);
$endD = strtotime($endDate);
$diffSeconds = $endD - $startD;
$days = ($diffSeconds / 86400);
for ($wd = 1; $wd < $days; $wd++)
{
	$weekdays = ($startD + 86400*($wd));
	echo date("d-m-Y",$weekdays) . "<br />";
}
?>

 

If you want the difference to include the first day, then change the for loop to $wd = 0.

 

thank you so much.. ^__^

[mhaey]

uhmm.. i notice that when the sdate was 01/01/2007 and edate was 01/08/2007.. the output was

 

01/01/2007

01/02/2007

01/03/2007

01/04/2007

01/05/2007

01/06/2007

01/07/2007

 

what about the enddate..

[mhaey]

uhmm.. i notice that when the sdate was 01/01/2007 and edate was 01/08/2007.. the output was

 

01/01/2007

01/02/2007

01/03/2007

01/04/2007

01/05/2007

01/06/2007

01/07/2007

 

what about the enddate..

 

never mind.. i figure it out already.. ^___^