sdaniels Posted April 12, 2006 Share Posted April 12, 2006 here is my code[code]$result = mysql_query("SELECT * FROM security_menu_main WHERE sec_level <= '$_SESSION[seclevel]' AND isactive = 'y'");[/code]the query is ignoring the "sec_level <= $_SESSION[seclevel]" and just checking if isactive is == ywhat am I doing wrong? Quote Link to comment Share on other sites More sharing options...
DougieB2 Posted April 12, 2006 Share Posted April 12, 2006 A tip is to echo out your query string, so you can see what's going on.[code]$query = "SELECT * FROM security_menu_main WHERE sec_level <= '$_SESSION[seclevel]' AND isactive = 'y'";echo "original query: " . $query;$query = "SELECT * FROM security_menu_main WHERE sec_level <= '" . $_SESSION['seclevel'] . "' AND isactive = 'y'";echo "new query: " . $query;$result = mysql_query($query);[/code] Quote Link to comment Share on other sites More sharing options...
hadoob024 Posted April 12, 2006 Share Posted April 12, 2006 hmm... maybe your problem is that $_SESSION variables are accessed using the following syntax:$_SESSION['seclevel']and in your query string, you're accessing the value using:$_SESSION[seclevel]maybe you're just missing the single quotes?i've also read about using the tickmarks (`) around table and field names. could this be what's missing? Quote Link to comment Share on other sites More sharing options...
sdaniels Posted April 12, 2006 Author Share Posted April 12, 2006 [!--quoteo(post=363894:date=Apr 12 2006, 12:14 AM:name=hadoob024)--][div class=\'quotetop\']QUOTE(hadoob024 @ Apr 12 2006, 12:14 AM) [snapback]363894[/snapback][/div][div class=\'quotemain\'][!--quotec--]hmm... maybe your problem is that $_SESSION variables are accessed using the following syntax:$_SESSION['seclevel']and in your query string, you're accessing the value using:$_SESSION[seclevel]maybe you're just missing the single quotes?i've also read about using the tickmarks (`) around table and field names. could this be what's missing?[/quote]thanks for the help, it turens out that i have a different problemthis code[code]$query = "SELECT user_sec_level FROM security_users WHERE user_name = '$name' AND user_password = '$password'";$sec_level = @mysql_query($query);$_SESSION[seclevel] = $sec_level;[/code]the problem that $sec_level is a vale of 'resource id #5' i need it to be the value that is in that that location in the table....im missing a step... any ideas? Quote Link to comment Share on other sites More sharing options...
BladeMetal Posted April 12, 2006 Share Posted April 12, 2006 [!--quoteo(post=363894:date=Apr 12 2006, 03:14 PM:name=hadoob024)--][div class=\'quotetop\']QUOTE(hadoob024 @ Apr 12 2006, 03:14 PM) [snapback]363894[/snapback][/div][div class=\'quotemain\'][!--quotec--]hmm... maybe your problem is that $_SESSION variables are accessed using the following syntax:$_SESSION['seclevel']and in your query string, you're accessing the value using:$_SESSION[seclevel]maybe you're just missing the single quotes?[/quote]no his syntax is 100% correct. When calling superglobals in something like an echo statement you can have:[code]echo 'This session superglobal equals $_SESSION[value]';[/code] Quote Link to comment Share on other sites More sharing options...
kulmacet Posted April 12, 2006 Share Posted April 12, 2006 [!--quoteo(post=363895:date=Apr 12 2006, 12:19 AM:name=sdaniels)--][div class=\'quotetop\']QUOTE(sdaniels @ Apr 12 2006, 12:19 AM) [snapback]363895[/snapback][/div][div class=\'quotemain\'][!--quotec--]thanks for the help, it turens out that i have a different problemthis code[code]$query = "SELECT user_sec_level FROM security_users WHERE user_name = '$name' AND user_password = '$password'";$sec_level = @mysql_query($query);$_SESSION[seclevel] = $sec_level;[/code]the problem that $sec_level is a vale of 'resource id #5' i need it to be the value that is in that that location in the table....im missing a step... any ideas?[/quote]TRY THIS Some changes have been made to the way you handle the variable$query = "SELECT user_sec_level FROM security_users WHERE user_name = '$name' AND user_password = '$password'";$sec_level = @mysql_query($query);$set = mysql_fetch_array($sec_level);$security_level = $set["user_sec_level"];$_SESSION[seclevel] = $security_level; Quote Link to comment Share on other sites More sharing options...
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