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Ok this is my basic folder setup:

 

localhost/

    --myprogram(directory)

        --functions.php

        --includes(directory)

                --join.php

        --photos(directory)

        --join.php

        --themes(directory)

                --default(directory)

                        --joinform_body.tpl

 

the file 'functions.php' contains a function that copies a file selected from the user's computer with a form('themes/default/joinform_body.tpl').  includes/join.php is the file that is using the copy_photo function.  What syntax would I have to use to copy the file to the photos directory?

 

copy( $photoname, "$dir" ) or

          die("There was an error uploading your photo.  Please try again later.");

 

That's my copy function where the directory should be localhost/myprogram/photos. 

$dir = "/photos";

 

How would I do that?  I tried just plain photos but it says the directory doesn't exist so I'm thinking the script thinks it's includes/photos.

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https://forums.phpfreaks.com/topic/71790-including-file-in-parent-folder/
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To get to a parent directory you use ".."

 

For example in the following file system

 

--mmmvomit
  +-wwwroot
  | +-index.php
  | +-profile.php
  +-img
  | +-logo.gif
  | +-annoyingani.gif
  | +-lolcat.gif
  +-error_log.txt
  +-usernames.txt

 

If I want to access 'error_log.txt' from within 'index.php', I can do it like this.

 

$foo = file("../error_log.txt");

 

The '..' means "go to the parent directory."  Since index.php is in wwwroot, the parent directory is mmmvomit.  '../error_log.txt' then translates to '/mmmvomit/error_log.txt'.

 

If I want to get at one of the files in the img folder from within index.php, I would do something like this.

 

<img src="../img/lolcat.gif">

 

The '..' translates to the parent directory of wwwroot, which is mmmvomit.  From there it looks in the img folder, then retrieves lolcat.gif.

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