Notice: Undefined offset: 1 in ....

[kraadde]

I have following code:

 

function chk( & $var ){
    if ( !isset($var) ){
        return NULL;
    }else{
        return $var;
    }
}

chk($loop);
.....
chk($y);
$y = 0;

while (($loop[$y]) != ''){                          error here ?????????? 
            ........  
            $y++; 
        }
......

 

Does anybody know how to fix this? I can not figure out why there should be an undefined offset .

 

HELP ME PLEASE!

 

kraadde

[MmmVomit]

Change this

 

while (($loop[$y]) != ''){ 

 

to this

 

while (isset($loop[$y])){ 

 

Or you could just use a foreach loop.