how would I

[madspof]

I have a script that i want to change a mysql database if a variable contains information, and then to go on to display the information but if the variable does not conatin any informatiion i want it to skip the changing process and just display the information from the db

here is my code but i am not sure how to finish this off can come one help me out;

  <?php
  // Check if there is a cookie, if there isn't then exit!
  if (!isset($_COOKIE['cookie_info'])) {
      echo "You are not logged in.";
  exit;
       }
elseif (!isset($_COOKIE['cookie_info1'])) {
echo "You are not an admin.";
exit;
}
else{
include 'connect.php';
$change = "";
$change = $_GET["Authorised"];
if(preg_match('/[A-Za-z0-9]/', $change)==TRUE){


$letter = array("a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z");
$numbers = array("1", "2", "3", "4", "5", "6", "7", "8", "9", "0", " ");
#
$user = str_replace($numbers, "", $change);
$auth = str_replace($letter, "", $change);
echo "$user <BR> " .
 "$auth <BR> ";
mysql_query("UPDATE members SET Authorised = '$auth' WHERE Gamertag= '$user'") or die(mysql_error());
}else{
$activate = "";
$query  = "SELECT Gamertag, Authorised FROM members";
$result = mysql_query($query);
$count = 1;
while($row = mysql_fetch_assoc($result))
{
if($row['Authorised'] == 0){
$activate = "<a href='updateusers.php?Authorised=1$row[Gamertag]'>Deactivated
</a>";
}
else{
$activate = "<a href='updateusers.php?Authorised=0$row[Gamertag]'>Activated
</a>";
}
echo "Name :{$row['Gamertag']} <br>" .
         "Account status : $activate <br>";

$count++;         
}
}
}
?>