johnqpublic24 Posted July 16, 2003 Share Posted July 16, 2003 Thanks for looking - I\'m trying to create a field where people can enter existing records in a database. When the PHP page first loads, they are prompted to enter the number of the record they want to change. When they enter their record, the page reloads and displays the fields of that record in text boxes. The user then has the option of changing the data and clicking the Update button. I can pull up the record fine, but the code that processes the revised information gives me a strange error message: Parse error: parse error, unexpected $end in c:public_htmlupdate.php on line 113 Where line 113 is the last line of the page. When I pull out the if (isset($_POST[\'submit\'])): block the code works fine, but with no update when submitted. Does anyone have any ideas what I\'m doing wrong? <html> <head> <title> View Client </title> </head> <body> <?php // Connect to the database server $dbcnx = @mysql_connect(\'localhost\'); if (!$dbcnx) { die( \'<p>Unable to connect to the \' . \'database server at this time.</p>\' ); } // Select the jokes database if (! @mysql_select_db(\'online\') ) { die( \'<p>Unable to locate the \' . \'database at this time.</p>\' ); } ?> <?php if (isset($_POST[\'submit\'])): $dbcnx = mysql_connect(\'localhost\'); mysql_select_db(\'online\'); $Status = $_POST[\'Status\']; $sql = \"UPDATE data SET Status=\'$Status\' WHERE SessionID=\'$results\'\"; if (@mysql_query($sql)) { echo(\'<p>data added</p>\'); } else { echo(\'<p>Error adding new data: \' . mysql_error() . \'</p>\'); } ?> <?php if (isset($_GET[\'record\'])): $record = $_GET[\"record\"]; echo(\"$record\"); echo(\"<form action=\'$_SERVER[PHP_SELF]\' method=post>\"); echo(\'<table border=1 cellpadding=5><TR bgcolor=\"#e5e5e5\"><TD>SessionID</TD><TD>Student Number</TD><TD>First Name</TD><TD>Last Name</TD><TD>Email</TD><TD>Status</TD></TR>\'); $result = @mysql_query(\"SELECT SessionID, StudentNumber, FirstName, LastName, Email, Status FROM data WHERE SessionID=\'$record\'\"); while ($row = mysql_fetch_array($result) ) { $SessionID=$row[\'SessionID\']; $StudentNumber=$row[\'StudentNumber\']; $FirstName=$row[\'FirstName\']; $LastName=$row[\'LastName\']; $Email=$row[\'Email\']; $Status=$row[\'Status\']; echo(\'<TR bgcolor=\"#e5e5e5\"><TD>\' .$SessionID . \'</TD><TD><input type=text name=StudentNumber value=\' .$StudentNumber . \'></TD><TD><input type=text name=FirstName value=\' .$FirstName . \'></TD><TD><input type=text name=LastName value=\' .$LastName . \'></TD><TD><input type=text name=Email value=\' .$Email . \'></TD><TD><input type=text name=Status value=\' .$Status . \'></TD></TR>\'); } echo(\'<input type=submit name=submit value=submit></form>\'); ?> <?php else: // Allow the user to enter a new author ?> <form action=\"<?=$_SERVER[\'PHP_SELF\']?>\" method=\"get\"> <p>Look up a client (using session ID #):<br /> Email: <input type=\"text\" name=\"record\" size=\"20\" maxlength=\"255\" /><br /> <input type=\"submit\" value=\"lookup\"></p> </form> <?php endif; ?> </body> </html> [/code] Quote Link to comment Share on other sites More sharing options...
holiks Posted July 16, 2003 Share Posted July 16, 2003 ...maybe because of incorrect use of \'if\' statement? [php:1:b602e2cd6d] if(isset($_POST[\'submit\'])): { //do something } else { //do something else } [/php:1:b602e2cd6d] ..is wrong ..but you did use it right the second time which is maybe why that worked.. [php:1:b602e2cd6d] if (isset($_GET[\'record\'])): //do something else: // Allow the user to enter a new author endif; [/php:1:b602e2cd6d] ..use the first if statement u mentioned like u did the second Quote Link to comment Share on other sites More sharing options...
johnqpublic24 Posted July 16, 2003 Author Share Posted July 16, 2003 thanks! Quote Link to comment Share on other sites More sharing options...
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