stripping left ended zeros off a number

[cooldude832]

I got a number like

$day = 08;

and I want it to be

$day = 8;

 

however day could also be

$day = 19;

 

and I don't just want to auto strip that any ideas?

[thedarkwinter]

try:

 

$day = intval($day);

 

should do the trick.

 

cheers,

tdw

[cooldude832]

I did this

<?php
		if(strpos($date_data[2],0) == 0){
			$tday = substr($date_data[2],1,1);
		}
		else{
			$tday = $date_data[2];
		}
?>

where $date_data[2] is that day nubmer in question.

[MadTechie]

erm.. no use

$day =(int) $day;

 

[cooldude832]

I solved that issue, but now i'm using the date function and usnig the indentiacl mktime field getting 2 different dates

 

<?php
		$date = date("l nS \of F Y",mktime(0,0,0,$date_data[1],$date_data[2],$date_data[0]));
		$date2 = date("M-d-Y",mktime(0,0,0,$date_data[1],$date_data[2],$date_data[0]));
?>

Date 1: Saturday 6th of June 2002

Date 2: Jun-08-2002

 

How can this be they are the same identical mktime() ???

[thedarkwinter]

date("l nS \of F Y")

 

n = month number

use d instead

[thedarkwinter]

or "j" rather for no leading zeros

[MadTechie]

can you print_r($date_data);

a common problems is having the 5th param as a zero, which refers to, todays day..