[SOLVED] Page Numbering..... 10 either side of the current page......

[scooter41]

Hi There....

 

I have a user based system I am creating, that has 97k users, so as you can imagine for page numbering I simply cant list every page number

 

I have a script that goes either side of the current page i.e if current page is 30, then page numbering starts from 20 and goes to 40 for example.

 

To do this I am using:

 

for($i = 1; $i <= $total_pages; $i++){

    if(($page) == $i){

 

        $pagelinks.= " |<span class='currPage'> $i </span>| ";

        } else {

 

if (($i < $page+10 && $i > $page-10 )){

            $pagelinks.="<a href=\"?page=$i$urlvars2\">$i</a> ";

}

    }

}

 

 

But my question is, is there anyway for the values under 10, for example, page 3 that only 10 page links are created instead of the regular 20, so it looks a bit inconsistent with the other pages. Is there a neat and tidy way to format that if statement to say if current page is under 10, bump up the top end limiter?

[Barand]

try this. It will also take care of the other end of the range when you get near the last page.

 

<?php
$total_pages = 100;
$page = isset($_GET['page']) ? $_GET['page'] : 1;                      // set from form for testing

if ($page < 1) $page = 1;
if ($page > $total_pages) $page = $total_pages;

if ($page < 10)
{
    $startnum = 1;
    $endnum = min(20, $total_pages) ;
}
elseif ($page > $total_pages-10)
{
    $startnum = max(1, $total_pages - 19);
    $endnum = min($page + 10, $total_pages);
}
else {
    $startnum = max(1, $page - 9);
    $endnum = min($page + 10, $total_pages);
}
for($i = $startnum; $i <= $endnum; $i++){
    if ($page == $i){
        $pagelinks.= " |<span class='currPage'> $i </span>| ";
    } else {
        $pagelinks.="<a href=\"?page=$i$urlvars2\">$i</a> ";
    }
}
echo $pagelinks;
?>
<form>
<input type="text" name="page" size="5">
<input type="submit" name="sub" value="Submit">
</form>

[scooter41]

Thats perfect! Works really great....... thanks