adrianTNT Posted October 18, 2007 Share Posted October 18, 2007 I got stuck at something that I thought it was simple I have this code: do { echo $row_Recordset_count_referers['referer_url']; } while ($row_Recordset_count_referers = mysql_fetch_assoc($Recordset_count_referers)); That block will return site referers form database like this: some_site.com some_site.com some_other_site.com some_other_site.com some_other_site.com How can I display each unique record and total instances next to it (sorted descending)? so that it looks like this: site.com (4); other_site.com(2) foo_site(1) Can someone provide a code block? Or at least Instructions? Thank you. Quote Link to comment Share on other sites More sharing options...
Wuhtzu Posted October 18, 2007 Share Posted October 18, 2007 It is quite simple <?php $getreferrers = mysql_query("SELECT referrer, COUNT(referrer) AS count FROM products GROUP BY referrer ORDER BY count DESC"); ?> This will allow you to do <?php while($row = mysql_fetch_array($getreferrers)) { echo $row['referrer'] . "(" . $row['count'] . ")"; } ?> Quote Link to comment Share on other sites More sharing options...
adrianTNT Posted October 18, 2007 Author Share Posted October 18, 2007 Thank you Wuhtzu I adjusted row names a bit and the code worked nicely. Have a great day. Quote Link to comment Share on other sites More sharing options...
Wuhtzu Posted October 18, 2007 Share Posted October 18, 2007 Since you did not give any field names I had to make them up, but I'm glad to hear it worked Quote Link to comment Share on other sites More sharing options...
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