allow_url_fopen

[php4ever]

I'm trying to create a simple template version notification snippet and I'm missing something but what I'm not sure;

 

<?php
function version_check()
{
$template_version = '2.5';
if (ini_get("allow_url_fopen") == 1) {
	$lastest_version = @file_get_contents("http://www.jaredritchey.com/downloads/601.txt");
	$check = version_compare($template_version, $lastest_version, ">=");
}

}
echo($latest_version);
?>

 

The idea is to look at a directory and compare versions.  If there is a newer one then echo a statement or something.  If not echo nothing.

 

Is allow_url_fopen a down graded function or did I just approach this wrong?

 

~ Jared

[enoyhs]

You know that echo statement should be before last brackets and that is function so you need to call it to work?

[php4ever]

Thank you sincerely for your reply. 

 

 

I've removed the echo actually but the function call?  What again on the syntax to display the results?

 

~ Jared

[enoyhs]

I quite didn't understand your question...

 

What I mean with function call is you need to call function like this: version_check();

 

So the full code would be:

<?php
function version_check()
{
$template_version = '2.5';
if (ini_get("allow_url_fopen") == 1) {
	$lastest_version = @file_get_contents("http://www.jaredritchey.com/downloads/601.txt");
	$check = version_compare($template_version, $lastest_version, ">=");
}	
echo($latest_version);
}
?>
version_check();