Dropdown menu default on page load

[john6384]

I am populating a drop down list from mysql DB using PHP.

 

Then javascript changes a tables content below according to the value selected.

 

Problem is I want it to have the last option chosen when the tables is loaded (refreshed).

 

Any more explantion then please say.

 

<script language="javascript" type="text/javascript" >
function jumpto(formIn)
{		
	var form = formIn;

	form = form.users.options[form.users.options.selectedIndex].value;		
	self.location='BugList.php?userName=' + form;
}
</script>

[MadTechie]

if you want a javascript solution then your in the wrong section, as for a php solution try this

 

<?php
$myarray = array("test1" => 1, "test2" => 2, "test3" => 3);

echo "<form method=\"POST\" enctype=\"application/x-www-form-urlencoded\">\n";
echo "<select name=\"test\">\n";
foreach($myarray as $K => $V)
{
$sel = ($V == $_POST['test'])?"selected = \"selected\"":"";
echo "<option value=\"$V\" $sel>$K</option>\n";
}
echo "</select>\n";
echo "<input type=\"submit\" value=\"tester\" />\n";
echo "</form>\n";
?>