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Hi I am trying o uploa some files into mysql database by keep getting the error message

 

 

Warning: fread(): supplied argument is not a valid stream resource in C:\Program Files\xampp\htdocs\upload.php on line 4

 

File ID: 0

 

File Name:

 

File Size:

 

File Type:

 

To upload another file Click Here

 

I have an html form

 

<form method="post" action="upload.php" enctype="multipart/form-data">
Description:<br>
<input type="text" name="form_description" size="40">
<input type="hidden" name="MAX_FILE_SIZE" value="1000000000">
<br>File to upload:<br>
<input type="file" name="form_data" size="40">
<p><input type="submit" name="submit" value="submit">
</form>

 

and a php handling script

 

<?php
mysql_connect("localhost","root","");
mysql_select_db("database_name");
$data = addslashes(fread(fopen($form_data, "r"), filesize($form_data)));
$result=MYSQL_QUERY("INSERT INTO uploads (description, data,filename,filesize,filetype) ". "VALUES ('$form_description','$data','$form_data_name','$form_data_size','$form_data_type')");
$id= mysql_insert_id();
print "<p>File ID: <b>$id</b><br>";
print "<p>File Name: <b>$form_data_name</b><br>";
print "<p>File Size: <b>$form_data_size</b><br>";
print "<p>File Type: <b>$form_data_type</b><p>";
print "To upload another file <a href=http://localhost/upload.html> Click Here</a>";
?>

 

I have been through the code and seached the forum but can't find a resolution so I would really appreciate some help!

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Thanks for your reply, I missed the database name previously which I have now put in but I still get the message. I also read the link you kindly put up and to be honest being new to php I am not really any wiser as I want to put the data into an database and this explains putting it into a file?

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