[SOLVED] ?page=

[jkewlo]

hello im wondering how i would go about getting a url like to look like this www.blah.com/?page=index and now www.blah.com/index.php

 

please get back to me asap thanks a million!

[Wuhtzu]

Your question is lost in the incorrect sentence...

 

You mention two types of urls:

 

www.blah.com/?page=index and www.blah.com/index.php

 

Which do you want?

[jkewlo]

i want it to look like www.blah.com/?page=index or when u click a link it would be www.blah.com/?page=login etc... instead of having the links show in the address bar like www.blah.com/index.php? or www.blah.com/login.php?

 

what would i do to make it like that i know i have to use the $_GET method to do it i just need a guide to show me

[pocobueno1388]

It sounds like you have a mod rewrite on the url...go to your .htaccess file and look for code that looks similar to this -

http://www.trap17.com/index.php/php-mod-rewrite-tutorial_t10219.html

[jkewlo]

hemm not sure if that is it.

kk

 

here is a example

 

elcire.no-ip.org/elcire if u look at the links u will see what i am talking about

[Dragen]

it could be .htaccess or it could just be a simple get function.

 

It could all be running off the index.php page which collects the get var and includes the correct file.

eg:

<a href="http://www.blah.com/?page=index">link</a>

then in blah.com/index.php:

require($_GET['page'] . '.php');

 

obviously this is a very simple example. You'll want some security on it.

[jkewlo]

so it would have to include page and then $_GET it

 

[Dragen]

no. What my example was doing was using the index,php, it was collecting the value of $_GET['page']. Then using 'require' to include another php page, where the filename was the value of $_GET['page'], with the added .php part at the end for the file extension.

 

So if you had a link like this:

<a href="http://www.mydomain.com/?page=info

Then this code:

require($_GET['page'] . '.php');

Would include the file http://www.mydomain.com/info.php