madcrazy1 Posted October 30, 2007 Share Posted October 30, 2007 hi i cant get the javascript to work inside echo. i need the window to pop up. echo ("<a href='.$zeb.' onclick=\"window.open('.$zeb.','popup','width=440,height=290,left=165,top=140'); return false\"><img src='.$ICON.' border='0'></a>"); thanks! Link to comment https://forums.phpfreaks.com/topic/75347-popup-inside-echo/ Share on other sites More sharing options...
rajivgonsalves Posted October 30, 2007 Share Posted October 30, 2007 here you go you where not ending the string properly echo ("<a href='".$zeb."' onclick=\"window.open('".$zeb."','popup','width=440,height=290,left=165,top=140'); return false\"><img src='".$ICON."' border='0'></a>"); Link to comment https://forums.phpfreaks.com/topic/75347-popup-inside-echo/#findComment-381053 Share on other sites More sharing options...
0x00 Posted October 30, 2007 Share Posted October 30, 2007 Here's my version... echo ("<a href=".$zeb." onclick='window.open(".$zeb.",'popup','width=440,height=290,left=165,top=140'); return false'><img src=".$ICON." border='0'></a>"); Link to comment https://forums.phpfreaks.com/topic/75347-popup-inside-echo/#findComment-381055 Share on other sites More sharing options...
aschk Posted October 30, 2007 Share Posted October 30, 2007 Here's my version : echo "<a href={$zeb} onclick='window.open(\'{$zeb}\',\'popup\',\'width=440,height=290,left=165,top=140\'); return false'> <img src={$ICON} border='0'> </a>"; Link to comment https://forums.phpfreaks.com/topic/75347-popup-inside-echo/#findComment-381062 Share on other sites More sharing options...
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