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You can do this using sessions. Put this code at the top of your header page so it is executed each time the user clicks.

 

<?php

//No session set (first time user visited)
if(empty($_SESSION['last_active'])){
//Set the Session
$_SESSION['last_active'] = time();
}

//Session set, but user not active for more than thirty minutes
elseif(!empty($_SESSION['last_active']) && $_SESSION['last_active'] < time()-1800){
print "Your session timed out.";

//Destroy the session
$_SESSION['last_active'] = '';
exit;
}

//Session set, and the user has been active for under thirty minutes
elseif(!empty($_SESSION['last_active']) && $_SESSION['last_active'] >= time()-1800){
//Update session with current time
$_SESSION['last_active'] = time();
}

?>

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Not sure this would work

elseif(!empty($_SESSION['last_active']) && $_SESSION['last_active'] < time()-1800){

print "Your session timed out.";

 

If you leave alone for more than 30 minutes the session will be gone anyway. I think he wants the server to log a timeout.

 

Desmond.

 

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If you leave alone for more than 30 minutes the session will be gone anyway. I think he wants the server to log a timeout.

 

It all depends on what they have set in there ini file to how long the session will last. I don't see anything in their post that refers to wanting to log it...

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