[SOLVED] Expression to show date status

[hostfreak]

Hey, I'm storing a date in a database. The date will represent when something expires. I can show when it's expired or current, but I am unsure how to give a notice when it will be expiring within x days up until expiring. Here is what I have:

<?php

    //Dates
    $current = date('Y-m-d');
    $expires = '2007-11-07';
    $notice  = date('Y-m-d', mktime($expires) - 5 * 24 * 60 * 60); //try an interval of 5 days
    
    //Date Status
    if ($current >= $expires)
    {
        echo 'Expired';
    }
    else if () //this is where I am unsure
    {
        echo 'Expiring within x days';
    }
    else
    {
        echo 'Current';
    }

?>

 

By the way, I know I can do this via mysql, but want to know they way via php. Thanks in advanced.

[rajivgonsalves]

$expires is it in seconds, hours... etc..

[hostfreak]

$expires contains the date (Y-m-d) that it will expire. If that is what you were asking?

[rajivgonsalves]

maybe this is what you wants

 

http://www.ilovejackdaniels.com/php/php-datediff-function/

[hostfreak]

I don't quite think that is what I want. I don't need it to list exactly how many days until the expired date, just inform them if it is within x days of expiring. Although, that could be nice. However for the sake of simplicity, just show within the x days. So say within 32 days; it could be 32 or even 10, but it would still say "Within 32 days". Unless of course it is expired or current. Thanks for the responses so far.

[hostfreak]

Anyone have any ideas? Thanks.

[hostfreak]

Just for anyone curious, I have figured out a solution. Was easier than I thought; was just a matter of not being so lazy. Here is the solution:

<?php

    //Dates
    $current = date('m-d-Y');
    $expires = '2007-11-09'; //Date that the " " expires. Can be an expiration of anything. Can also be pulled from a database. Must be in Y M D formatt, unless you want to edit the code
    list($year, $month, $day) = explode('-', $expires);    
    $notice =  date('m-d-Y', mktime(0, 0, 0, $month, $day, $year) - (5 * 24 * 60 * 60)); //Subtract x amount of days (5 in this case) from the expiring date to start the expiring notice.
    
    //Date Status
    if ($current >= $expires)
    {
        echo 'Expired';
    }
    else if ($current >= $notice && $current <= $expires)
    {
        echo 'Expiring within 5 days';
    }
    else
    {
        echo 'Current';
    }

?>