post issue

[Jay2391]

Okay here is my issue , I am weak at the posting and HTML deal...

 

So i have a simple drop down and I want that when i select from the drop down and click submit

 

that my browser will change to website.php?get_something=$i&another=$b

 

the issue is that the first time i click submit it sytays the same ...the second time it changes to the prior selection...

 

I do not want to click twice to get my result any Ideas...here is the code i clean  it up a lot but that is the main idea

 

$i= $_GET['i']; 
$b = $_GET['b'];   
    
echo "$i  and $b";


         print "<form action=md_challenge.php?i=$i&a=TRUE method='post'>";       

         <select class="newsmall" name="i"> 
         <option value="1">opt1</option></p>
         <option value="2">opt2</option></p>
         <option value="3">3</option></p>
         </select		 

         <input type="submit" name="submit" size"20" value="submit">";

}

[otuatail]

Not sure what you mean by change to website.php. Are you trying to load a diffrent page depending on the value of the drop down box. What php pages are used?

 

 

[Jay2391]

is a ticky form so i use the same page ....md_challenge.php in this case

 

the issue is that the first time  click submit ..

 

 

the browser shows...

$i =100;

 

md_challenge.php?i=&a=

 

the secint time i click submit i get

 

md_challenge.php?i=100&a=TRUE

 

 

[otuatail]

Ok then this is probably what you need to do

 

If you are posting back to the same page with the drop down list.

The first thing you need to do is get the selected value of the drop down.

 

$Value = $_POST['i'];

 

// Then make that the current selection

 

<select class="newsmall" name="i">

<option value="1"<? if($value == 1) {?> SELECTED <?}?>>opt1</option>

<option value="2"<? if($value == 2) {?> SELECTED <?}?>>opt2</option>

</select>

 

Desmond

[Jay2391]

that won't work i still have to click submit twice to get the result

 

my issu is not the diplay is why the first time i click submit

 

I do not get the result post on the browser???

[Jay2391]

all my code is inside php FYI

[otuatail]

in your code you didn't have SELECTED in the code so it could not have changed.  What do you mean by I do not get the result post on the browser?

 

Is ther some code missing? why does your submit button have size"20"

this dosn't do anything. Maybee more of the code? as this should work.

place an echo $Value; after the $Value = $_POST['i'];

This should have the value.

[Jay2391]

Hope this clarifies you question on what I am looking for....

 

/////the code is inside md_challenge.php
<?php

$i =100;

////the browser shows...

/////md_challenge.php?i=&a=

/////the second time I click submit i get 

/////md_challenge.php?i=100&a=TRUE

$i= $_GET['i']; 
$b = $_GET['b'];   
    
echo "$i  and $b";


         print "<form action=md_challenge.php?i=$i&a=TRUE method='post'>";       

         <select class="newsmall" name="i"> 
         <option value="1">opt1</option></p>
         <option value="2">opt2</option></p>
         <option value="3">3</option></p>
         </select		

         <input type="submit" name="submit" size"20" value="submit">";

}
?>

[phpSensei]

i did not understand you.

 

<?php

// Sorry dude, i dont understand what you mean... but

$i = 1; // change this to whatever
$b = 2; // also change

print "<form action ='".$_SERVER['PHP_SELF']."?i=".$i."&&b=".$b."' method = 'post' > <select class="newsmall" name="i"> 
         <option value=\"1\">opt1</option></p>
         <option value=\"2\">opt2</option></p>
         <option value=\"3\">3</option></p>
         </select>		

         <input type=\"submit\" name=\"submit\" size\"20\" value=\"submit\">
</form>";
?>

[otuatail]

Sorry I miised one of your lines in a reply

the browser shows...

$i =100;

 

$i= $_GET['i'];

$b = $_GET['b'];

WRONG

 

$i= $_POST['i'];

$b = $_POST['b'];