[SOLVED] three conjoined tests in php conditional fails?

[aplacito]

Perhaps I'm just crazy this morning, but it seems that one cannot use three tests joined with && in a php conditional.  For example, the following code works:

 

$errors = 0;
if ($submitted) {
     if(($_POST['un'] != "") && ($_POST['pw'] != "")) {
             $errors = 2;
     }
}
//when $submitted is true, $errors is 2,
//when $submitted is false, $errors is 0.

 

but the following doesn't work properly:

 

$errors = 0;
if ($submitted && ($_POST['un'] != "") && ($_POST['pw'] != "")) {
     $errors = 2;
}
//when $submitted is true, $errors is 2,
//when $submitted is false, $errors is 2.

 

am I missing something completely?  can anyone confirm or refute this oddity?

[Psycho]

It should work, but you can simplify the code by losing the extra parens and using empty():

 

if ( $submitted && !empty($_POST['un']) && !empty($_POST['pw']) ) {

[aplacito]

thanks for the quick response, mjdamato.

 

i'm still seeing if there might be other errors in the code, but i'm still coming up dumbfounded.  thanks for the advise on !empty() though, i always enjoy cleaning up my code 

[LemonInflux]

<?php

$errors = 0;

if(isset($submitted)) && isset($_POST['un']) && isset($_POST['pw'])) {
     $errors = 2;
}

?>

 

Try that.

[Psycho]

I assume that the OP is checking the posted fields to see if the user entered data. If that is the case, using isset() for a posted value is not enough. If a field is empty when POSTED then it is set as an empty string.