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[SOLVED] Upload More images

emediastudios

By emediastudios
in PHP Coding Help

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emediastudios Advanced Member

emediastudios

Posted
Posted

I have this code that works good, just have to implement some filters.

How would i change this code if i wanted to add 3 images instead of just the 1.

I have input fields and fields in my database called photo1, phot02 and photo3.

 

<?php require_once('../Connections/gcproperty.php'); ?>
<?php 

//This is the directory where images will be saved 
$target = "../images/news/"; 
$target = $target . basename( $_FILES['photo']['name']); 

//This gets all the other information from the form 
$headline=$_POST['headline']; 
$link=$_POST['link']; 
$content=$_POST['content']; 
$photo1=($_FILES['photo'1]['name']); 





//Writes the photo to the server 
if(move_uploaded_file($_FILES['photo1']['tmp_name'], $target)) 
{ 


//Tells you if its all ok 
print "<meta http-equiv=\"refresh\" content=\"0;URL=news_added_successfully.php\">"; 
//Writes the information to the database 
mysql_query("INSERT INTO `news` VALUES ('$headline','$photo1','$content','$link')") ; 
} 
else { 

//Gives and error if its not 
echo "Sorry, there was a problem uploading your file."; 
} 
?>

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emediastudios Advanced Member

emediastudios

Posted
  • Author
Posted

i changed my code to this.

<?php require_once('../Connections/p2w.php'); ?>
<?php 

//This is the directory where images will be saved 
$target = "../news/"; 
$target = $target . basename( $_FILES['photo1']['name']); 

//This gets all the other information from the form 
$headline=$_POST['headline']; 
$contents=$_POST['contents']; 
$photo1=($_FILES['photo1']['name']); 
$photo2=($_FILES['photo2']['name']); 
$photo3=($_FILES['photo3']['name']);
$title1=$_POST['title1']; 
$title2=$_POST['title2'];
$title3=$_POST['title3'];  
$link=$_POST['link']; 





//Writes the photo to the server 
if(move_uploaded_file($_FILES['photo1']['tmp_name'], $target)) 
{ 


//Tells you if its all ok 
echo "Success."; 
//Writes the information to the database 
mysql_query("INSERT INTO `news` VALUES (NULL,'$headline','$contents','$photo1','$photo2','$photo3','$title1','$title2','$title3','$link')") ; 
} 
else { 

//Gives and error if its not 
echo "Sorry, there was a problem uploading your file."; 
} 
?>

Only uploads the one file, i know why but how i get it to do the 3?

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emediastudios Advanced Member

emediastudios

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Posted

Thanks for your help.

I did as you said and get this error

Parse error: syntax error, unexpected $end in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 39

 

My code looks like this now

<?php require_once('../Connections/p2w.php'); ?>
<?php 

//This is the directory where images will be saved 
$target = "../news/"; 
$target = $target . basename( $_FILES['photo']['name']); 

//This gets all the other information from the form 
$headline=$_POST['headline']; 
$contents=$_POST['contents']; 
$photo1=($_FILES['photo1']['name']); 
$photo2=($_FILES['photo2']['name']); 
$photo3=($_FILES['photo3']['name']);
$title1=$_POST['title1']; 
$title2=$_POST['title2'];
$title3=$_POST['title3'];  
$link=$_POST['link']; 





//Writes the photo to the server 
for ($x=1;$x<=3;$x++){
    $photo ='photo'.$x;
    if(move_uploaded_file($_FILES[$photo]['tmp_name'], $target)){


//Tells you if its all ok 
echo "Success."; 
//Writes the information to the database 
mysql_query("INSERT INTO `news` VALUES (NULL,'$headline','$contents','$photo1','$photo2','$photo3','$title1','$title2','$title3','$link')") ; 
} 
else { 

//Gives and error if its not 
echo "Sorry, there was a problem uploading your file."; 
} 
?>

 

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teng84 Member

teng84

Posted
Posted 

<?php require_once('../Connections/p2w.php');
//This is the directory where images will be saved 
$target = "../news/"; 
$target = $target . basename( $_FILES['photo']['name']); 
//This gets all the other information from the form 
$headline=$_POST['headline']; 
$contents=$_POST['contents']; 
$photo1=($_FILES['photo1']['name']); 
$photo2=($_FILES['photo2']['name']); 
$photo3=($_FILES['photo3']['name']);
$title1=$_POST['title1']; 
$title2=$_POST['title2'];
$title3=$_POST['title3'];  
$link=$_POST['link']; 
//Writes the photo to the server 
for ($x=1;$x<=3;$x++){
    $photo ='photo'.$x;
    if(move_uploaded_file($_FILES[$photo]['tmp_name'], $target)){
	//Tells you if its all ok 
	echo "Success."; 
	//Writes the information to the database 
	mysql_query("INSERT INTO `news` VALUES (NULL,'$headline','$contents','$photo1','$photo2','$photo3','$title1','$title2','$title3','$link')") ; 
} 
else { 
	//Gives and error if its not 
	echo "Sorry, there was a problem uploading your file."; 
} 
}
?>

 

you  missed }

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emediastudios Advanced Member

emediastudios

Posted
  • Author
Posted

I pasted your code over mine and now i get this.

Warning: move_uploaded_file(../news/) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 18

Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move 'C:\Windows\TEMP\php1CB6.tmp' to '../news/' in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 18
Sorry, there was a problem uploading your file.
Warning: move_uploaded_file(../news/) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 18

Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move 'C:\Windows\TEMP\php1CC7.tmp' to '../news/' in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 18
Sorry, there was a problem uploading your file.
Warning: move_uploaded_file(../news/) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 18

Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move 'C:\Windows\TEMP\php1CC8.tmp' to '../news/' in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 18
Sorry, there was a problem uploading your file.

???

 

Thanks for your help

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Demonic Advanced Member

Demonic

Posted
Posted

check your folder or dir mod bu sure its writable (777)

lol you don't need to chmod files on windows..

 

Your server might now allow that function, or its disabled.  Never seen that happen on a windows server to be honest.  Check if the directory your moving it to exists.

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teng84 Member

teng84

Posted
Posted

check your folder or dir mod bu sure its writable (777)

lol you don't need to chmod files on windows..

 

Your server might now allow that function, or its disabled.  Never seen that happen on a windows server to be honest.  Check if the directory your moving it to exists.

I have this code that works good, just have to implement some filters.

How would i change this code if i wanted to add 3 images instead of just the 1.

I have input fields and fields in my database called photo1, phot02 and photo3.

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emediastudios Advanced Member

emediastudios

Posted
  • Author
Posted

Changed this a little as i have this code in another site

<?php
for ($x=1;$x<=3;$x++){
   $photo ='photo'.$x;
   if(move_uploaded_file($_FILES[$photo . $x]['tmp_name'], $target)){
?>

Gave me this error

Sorry, there was a problem uploading your file.Sorry, there was a problem uploading your file.Sorry, there was a problem uploading your file.

could there b a problem here

$target = $target . basename( $_FILES['photo']['name']);

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teng84 Member

teng84

Posted
Posted

i should have seen that lol

put that inside the loop

for ($x=1;$x<=3;$x++){
    $photo ='photo'.$x;
$target = $target . basename( $_FILES[$photo]['name']); 
    if(move_uploaded_file($_FILES[$photo]['tmp_name'], $target)){
	//Tells you if its all ok 
	echo "Success."; 
	//Writes the information to the database 
	mysql_query("INSERT INTO `news` VALUES (NULL,'$headline','$contents','$photo1','$photo2','$photo3','$title1','$title2','$title3','$link')") ; 
} 
else { 
	//Gives and error if its not 
	echo "Sorry, there was a problem uploading your file."; 
} 
}

 

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emediastudios Advanced Member

emediastudios

Posted
  • Author
Posted

i should have seen that lol

put that inside the loop

for ($x=1;$x<=3;$x++){
    $photo ='photo'.$x;
$target = $target . basename( $_FILES[$photo]['name']); 
    if(move_uploaded_file($_FILES[$photo]['tmp_name'], $target)){
	//Tells you if its all ok 
	echo "Success."; 
	//Writes the information to the database 
	mysql_query("INSERT INTO `news` VALUES (NULL,'$headline','$contents','$photo1','$photo2','$photo3','$title1','$title2','$title3','$link')") ; 
} 
else { 
	//Gives and error if its not 
	echo "Sorry, there was a problem uploading your file."; 
} 
}

 

Works :);):D;D

Thanks heaps, Im so gratefull

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